To study the photochemical decomposition of aqueous bromine exposed to bright sunlight, we dissolved a small amount of liquid bromine in water contained in a glass jar and placed under direct sunlight. The following data were obtained at 25\deg C:\table [[Tiempo (min ), 10, 20, 30, 40, 50, 60], [Ppm, 2.45, 1.74, 1.23, 0.88, 0.62, 0.44]] Determine the reaction rate order and the specific reaction rate constant: a) Differential method ( The method for obtaining the derivatives is left to your decision) Tiempo (min) Ppm Br₂ 10 2.45 20 1.74 Ć 30 1.23 40 0.88 50 0.62 60 0.44

To study the photochemical decomposition of aqueous bromine exposed to bright sunlight, we dissolved a small amount of liquid bromine in water contained in a glass jar and placed under direct sunlight. The following data were obtained at 25\deg C:\table [[Tiempo (min ), 10, 20, 30, 40, 50, 60], [Ppm, 2.45, 1.74, 1.23, 0.88, 0.62, 0.44]] Determine the reaction rate order and the specific reaction rate constant: a) Differential method ( The method for obtaining the derivatives is left to your decision) Tiempo (min) Ppm Br₂ 10 2.45 20 1.74 Ć 30 1.23 40 0.88 50 0.62 60 0.44

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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1: Consider the loss of ozone in a dilute, low pressure Os/0, gas mixture in the steady state at standard (room) temperature due to the reactions, K O3 + 02 0+ 202 Ka (1) O3 +0 K2, 202 1.1 Write down the net reaction of reactions (1) & (2). Hence state the relative rate of O3 destruction to that of 02 creation. State the net rate of O destruction. 1.2 Write down the reaction rates (i.e. d/dt) for each of the three species. 1.3 Hence show that, K'no,noa K2No, + K3n, no 1.4 And that the rate of ozone destruction is given by, Lo, = 2K2nonos %3D 1.5 Hence derive an expression for Loa that is independent of O. 1.6 Using values of no, = 3.3 x 1010 m-3 and no, = 3.3 x 10 m-3 and the rate constants listed below, calculate the rate lose of ozone at 25 °C. K = 7.3 x 10-4 exp(-11400/T) m³ -s-1, K2 = 1.8 x 10-5 exp (-2300/T) m3 .s-1 K3 = 6.9 x 10-28 exp (300/T).25 m³.
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Iodine is sparingly soluble in water but much more so in carbon tetrachloride. The equilibrium constant, also called the partition coefficient, for the distribution of I2 between these two phases I2(aq) =12(CCI4) is 83 at 20°C. (a) A student adds 0.028 L of CCI4 to 0.213 L of an aqueous solution containing 0.037 g I2. The mixture is shaken and the two phases are then allowed to separate. Calculate the fraction of I2 remaining in the aqueous phase. 4.0 (b) The student now repeats the extraction of I2 with another 0.028 L of CCI4. Calculate the fraction of I2 from the original solution that remains in the aqueous phase. 4.0 (c) Compare the result in (b) with a single extraction using 0.056 L of CCI4. Comment on the difference. After a single extraction using 0.056 L of CCI4, the fraction of I2 that remains in the aqueous phase is 40 This result is larger than the result in (b), which means that a single large extraction is not as efficient as two separate smaller extractions.
Electrochemical Equilibria: Electrolytic DepositionOlympic gold medals are plated with gold rather than being pure gold. A minimum of 6 grams of gold (MW = 196.97 g/mol) and at least one gram of silver (MW = 196.97 g/mol) must be present in an Olympic gold medal.Silver content is 92.5 percent. A total of 340 gold medals were awarded at the Tokyo Olympics in 2021 to athletes who are deserving Assume each medal is made by coating a 60-mm diameter, 3-mm thick, gold-free silver disc with a gold-free coating. Determine the alloying of a disk with gold via electrolytic deposition using a gold (III) solution. following: a) Time in hours required to finish plating all gold medals used in the Tokyo Olympics If the available electricity source can deliver 50 current in amperes, the Olympics will have a minimum gold content.
In a study of the decomposition of ammonia on a platinum surface at 856 °C NH3¬1/2 N2 + 3/2 H, the following data were obtained: NH3), M 1.95x10-3 1.50x103 9.75x10-4 1.75x103 7.80×10-3 3.90x10-3 seconds 0 1000 Hint: It is not necessary to graph these data. (1) The observed half life for this reaction when the starting concentration is 7.80×103M is s and when the starting concentration is 3.90×103 Mis (2) The average rate of disappearance of NH3 from t= 0 s to t= 1000 s is ]Ms!. (3) The average rate of disappearance of NH3 from t= 1000 s to t= 1.50×103 s is ]Ms!. (4) Based on these data, the rate constant for this v order reaction is Ms!
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The activity of H,O in 35 wt% H,SO,, measured by lowering of the vapor pressure of H,0, is 4 = 0.66 at 25 °C.27 Activities of SO?- and H* cannot be measured separately, but the mean activity AlH,0 = mµ,0YH,0 can be measured. For a salt Cm A, with cation C"+ and anion A"-, the mean activity coefficient is defined as Y± = (r" r")m+n), where y, and y_ are the individual activity coefficients. The mean activity is a thermodynamically defined, measurable quantity. For 5.5 m H,SO,, Y± = (rj-Yso?-)3 = 0.22 at 25 °C27 (as measured from galvanic cells 0.22 in the Nernst equation, along with mµ = 11.0 mol/kg and containing H, SO,). Use A,0 = 0.66 and y± = 5.5 mol/kg, to calculate the voltage of the lead-acid battery. %3| mso?- Ecell V Incorrect
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Ethyl acetate reacts with sodium hydroxide when the two are mixed. The reaction, called ester hydrolysis, yields products ethyl alcohol and sodium acetate. The equation is CH3CO₂C₂H5(aq) + NaOH(aq) --> C₂H5OH(aq) + CH3CO₂Na(aq) The following data were obtained: Initial Concentration of CH3CO₂C₂Hs (mol L-¹) Initial Concentration of NaOH (mol L-¹) 0.005 0.010 0.005 0.010 0.020 0.020 The rate law for this reaction is: O Rate-k[CH3CO₂C₂H5]²[NaOH] O Rate-k[CH3CO₂C₂H5] + [NaOH] O Rate-k[CH3CO₂C₂H5]²[NaOH)² O Rate-k[CH3CO₂C₂H5] [NaOH] Initial Rate of Formation of C₂H5OH (mol L-1¹) 5.40 x 10-6 2.16 x 10-5 1.08 X 105
Given Zn(s)| Zn 2+ (aq) (1M) || Ag+2+ (aq) (1M) | Ag (s) Eocell = 1.562V What will the Ecell be if the [Zn2+] = 0.75M and [Ag+] =0.25 M at 40.00oC (313.15K)? The overall reaction is Zn(s) + 2 Ag+ (aq) --> 2 Ag (s) + Zn 2+ (aq) (Answer has 3 digits after the decimal)
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ΔΗ + AS AG0 unbe Gibb's Free Energy AG-AH-TAS -TAS Effect of Temperature on Spontaneity AG Reaction Characteristics