Tin(IV) sulfide, SnS2,SnS2, a yellow pigment, can be produced using the following reaction. SnBr4(aq)+2Na2S(aq)⟶4NaBr(aq)+SnS2(s)SnBr4(aq)+2Na2S(aq)⟶4NaBr(aq)+SnS2(s) Suppose a student adds 37.1 mL37.1 mL of a 0.529 M0.529 M solution of SnBr4SnBr4 to 41.5 mL41.5 mL of a 0.141 M0.141 M solution of Na2S.Na2S. Identify the limiting reactant. SnBr4SnBr4 NaBrNaBr Na2SNa2S SnS2SnS2
Tin(IV) sulfide, SnS2,SnS2, a yellow pigment, can be produced using the following reaction. SnBr4(aq)+2Na2S(aq)⟶4NaBr(aq)+SnS2(s)SnBr4(aq)+2Na2S(aq)⟶4NaBr(aq)+SnS2(s) Suppose a student adds 37.1 mL37.1 mL of a 0.529 M0.529 M solution of SnBr4SnBr4 to 41.5 mL41.5 mL of a 0.141 M0.141 M solution of Na2S.Na2S. Identify the limiting reactant. SnBr4SnBr4 NaBrNaBr Na2SNa2S SnS2SnS2
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Tin(IV) sulfide, SnS2,SnS2, a yellow pigment, can be produced using the following reaction.
SnBr4(aq)+2Na2S(aq)⟶4NaBr(aq)+SnS2(s)SnBr4(aq)+2Na2S(aq)⟶4NaBr(aq)+SnS2(s)
Suppose a student adds 37.1 mL37.1 mL of a 0.529 M0.529 M solution of SnBr4SnBr4 to 41.5 mL41.5 mL of a 0.141 M0.141 M solution of Na2S.Na2S.Identify the limiting reactant.
SnBr4SnBr4
NaBrNaBr
Na2SNa2S
SnS2SnS2
Calculate the theoretical yield of SnS2.SnS2.
theoretical yield:
gg
The student recovers 0.335 g0.335 g of SnS2.SnS2. Calculate the percent yield of SnS2SnS2 that the student obtained.
percent yield:
%
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