Tina is going to make iced tea by first brewing hot tea, then adding ice until the tea cools. Ice, at a temperature of −10.0°C, should be added to a 3.80 × 10−4 m3 glass of tea at 95.0°C to cool the tea to 10.0°C. The glass has a mass of 0.350 kg and the specific heat of the glass is 0.837 kJ/(kg·K). Specific heat capacity (15.0°C) of water is 4.186 kJ/(kg·K) and heat of fusion of water is 333.7 kJ/kg. Specific heat capacity of ice is 2.10 kJ/(kg·K). Find the mass of the ice required to cool the tea to 10.0ºC, without ignoring the temperature change of the glass. _______g
Tina is going to make iced tea by first brewing hot tea, then adding ice until the tea cools. Ice, at a temperature of −10.0°C, should be added to a 3.80 × 10−4 m3 glass of tea at 95.0°C to cool the tea to 10.0°C. The glass has a mass of 0.350 kg and the specific heat of the glass is 0.837 kJ/(kg·K). Specific heat capacity (15.0°C) of water is 4.186 kJ/(kg·K) and heat of fusion of water is 333.7 kJ/kg. Specific heat capacity of ice is 2.10 kJ/(kg·K). Find the mass of the ice required to cool the tea to 10.0ºC, without ignoring the temperature change of the glass. _______g
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Week 4 #13
Tina is going to make iced tea by first brewing hot tea, then adding ice until the tea cools. Ice, at a temperature of −10.0°C, should be added to a 3.80 × 10−4 m3 glass of tea at 95.0°C to cool the tea to 10.0°C. The glass has a mass of 0.350 kg and the specific heat of the glass is 0.837 kJ/(kg·K). Specific heat capacity (15.0°C) of water is 4.186 kJ/(kg·K) and heat of fusion of water is 333.7 kJ/kg. Specific heat capacity of ice is 2.10 kJ/(kg·K).
Find the mass of the ice required to cool the tea to 10.0ºC, without ignoring the temperature change of the glass.
_______g
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