Three transparent materials have indexes of refraction of n,=1.85; n,=1.50; and an unknown medium C, n=? A light ray is refracted in the materials from A to B and finally to C. Find the index of refraction of the unknown medium. Solve for theta and alpha. ne =? Interface n 1.85 27

The light ray shown in the figure makes anangle of 18.0◦ with the normal line at theboundary of linseed oil and water. a) Find the angle θ1. Note that n = 1.48for the linseed oil.Answer in units of ◦

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Light from a medium with index of refraction n1=2.49 passes into a medium with index of refraction n2=1.10. What is the critical angle where incoming light would all reflect off of the boundary, without passing into the second medium? Answer in degrees, °, measured from the normal.

When a light ray passes from a layer with index n1 = 1.5 to an adjacent layer with index n2, the ray deviates 10° from its initial direction as shown below. If the angle of incidence is e1 = 30°, then determine the value of the index n2. n2 n2 = 1.05 n2 = 1.26 n2 = 1.17 n2 = 1.48 n2 = 1.37

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11:19 Optics.pdf -> 2. Find angle ø. (Hint: Use Geometry skills.) 79.4712° Air, n, = 1 3. Find the second angle of 30 incidence. 10.5288° Horiz. ray, parallel to 4. Find the second angle of refraction, 0, using Snell's Law 15.9° base Glass, n = 1.5 Refraction Problem #2 Goal: Find the distance the light ray displaced due to the thick window and how much time it spends in the glass. Some hints given. 20° 0, 1. Find 0. 20° H,0 2. To show incoming & outgoing rays are parallel, find 0. 20° n, = 1.3 3. Find d. 0.504 m glass 10m 4. Find the time the light spends in the glass. n = 1.5 5.2 · 10-8 s Extra practice: Find 0 if bottom medium is replaced with air. H,0 26.4° Refraction Problem #3 Goal: Find the exit angle relative to the horizontal. 0 = 19.8° 36 air glass The triangle is isosceles. Incident ray is horizontal, parallel to the base.

Please refer again to Figure 2.   The incident ray is coming in from water (n=1.33) rather than air. And this time, theta = 52.2 degrees, y = 31.9 cm and h = 1.13 cm. What is x now?       33.6 cm     42.0 cm     12.6 cm     50.4 cm

2. A small light source (point source) is located in water (nr 1.33) at a depth d below the surface. Determine (a.) the critical angle for total reflection of light at the water-air interface (b.) the depth of the light source if an observer above the water sees an illuminated circle of 3m radius.

Consider a light ray that enters and exits a prism as shown below. Suppose the material of the prism is unknown but the surrounding material has index of refraction n, = 1.3. Find the index of refraction for the material of the prism. n2 n1 22° 38° 9. n, = А. 1.479 D. 1.586 В. 1.635 Е. 1.333 С. 1.389 F. 1.527