Three point charges are located on a circular arc as shown in the figure below. (Take r = 4.40 cm. Let to the right be the +x direction and up along the screen be the +y direction.) +3.00 nC -2.00 nC 30.0° 30.0° +3,00 nC (a) What is the total electric field at P, the center of the arc? E = 654 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully.î N/C + o v j N/C (b) Find the electric force that would be exerted on a -5.16-nC point charge placed at P. F = IN + 0 v JN

A cube has sides of length L = 0.370 m. It is placed with one corner at the origin as shown in the figure (Figure 1). The electric field is not uniform but is given by E =(-5.69 N/(C. m) )æi+(3.20 N/(C - m) )zk. Part A Find the electric flux through each of the six cube faces S1, S2, S3, S4, S5. and S6. Enter your answers numerically separated by commas. Eν ΑΣφ ? d1, Þ2, Þ3 , 4 , Þ5 , Þ6 = (N/C) - m² Submit Previous Answers Request Answer Part B Find the total electric charge inside the cube. ΑΣφ ? q = Figure 1 of 1 Submit Request Answer S2 (top) So (back) Provide Feedback S3 (right side) (left side) L L L. S, (bottom) S, (front)

please answer all parts and explanation.

State what is meant by electric field strength at a point in space. How is its direction defined? Given that the magnitude field strength, E, at a distance r from a point charge Q is given by the formula: E = 4πεο r2 calculate the magnitude of the electric field at a point which is 10 cm from a positive 24 µC charge. Use E = = 9 × 10° m/F. 4πεο

A cube has sides of length L = 0.370 m. It is placed with one corner at the origin as shown in the figure (Figure 1). The electric field is not uniform but is given by E =( -5.69 N/(C. m) )æi+( 3.20 N/(C · m) )zk. Part A Find the electric flux through each of the six cube faces Sı, S2, S3, S4, S5, and Sg- Enter your answers numerically separated by commas. ν ΑΣφ D1, Þ2 , D3 , Þ4 , Þ5 , Þ6 = (N/C) - m² Submit Request Answer Part B Find the total electric charge inside the cube. q = Figure 1 of 1 Submit Request Answer S2 (top) S6 (back) Provide Feedback S1 (left side) L - S3 (right side) y L L. S4 (bottom) S3 (front)

I keep getting this answer wrong can you help me because I don't understand it. Thank you.

I Rew A spherically symmetric charge distribution produces the electric field E =( 5700 r2)r N/C, where r is in m. Part A What is the electric field strength at r = 19.0 cm ? ? N/C Submit Request Answer Part B What is the electric flux through a 38.0-cm-diameter spherical surface that is concentric with the charge distribution? Nm2/C Submit Request Answer Part C How much charge is inside this 38.0-cm-diameter spherical surface? C

Please answer in typing format

need help on part A, C, D

y y :P2 B В Figure 2 Figure 1 a. i. Point P1, the intersection of the three bisectors, locates the geometric center of the triangle and is one point where the electric field is zero. On Figure 1 above, draw the electric field vectors EA, EB, and Ec at P1, due to each of the three charges. Be sure your arrows are drawn to reflect the relative magnitude of the fields.