Three identical blocks of massm on a frictionless surface are connected by massless taut strings. A force Fis applied on the rightmost block as shown in the figure below so that each block moves to right with acceleration a. m m m Applying Newton's second law on the rightmost block: EFx = = ma Applying Newton's second law on the block at the center: EFx = - T2 = Applying Newton's second law on the leftmost block: IFx = = ma If each block has a mass of 10 kg and is accelerating at 2 m/s2, the magnitude of the tension on the second string is T2 = N.

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Chapter6: Applications Of Newton's Laws
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QUESTION 1

Three identical blocks of mass m on a frictionless surface are connected by massless taut strings. A force F is applied on the rightmost block as shown in the figure below so that each block moves to right with acceleration a.

 

Applying Newton's second law on the rightmost block:

ΣFx = ________+________ = ma

Applying Newton's second law on the block at the center:

ΣFx = _______- T2 = ________

Applying Newton's second law on the leftmost block:

ΣFx =_________= ma

If each block has a mass of 10 kg and is accelerating at 2 m/s2, the magnitude of the tension on the second string is T2 = _________N. 

QUESTION 1
Three identical blocks of mass m on a frictionless surface are connected by massless taut strings. A force Fis applied on the rightmost block as
shown in the figure below so that each block moves to right with acceleration a.
T2
F
m
Applying Newton's second law on the rightmost block:
ΣFx
= ma
Applying Newton's second law on the block at the center:
EFx =
|- T2 =
Applying Newton's second law on the leftmost block:
EFx =
= ma
If each block has a mass of 10 kg and is accelerating at 2 m/s2, the magnitude of the tension on the second string is T2 =
N.
Transcribed Image Text:QUESTION 1 Three identical blocks of mass m on a frictionless surface are connected by massless taut strings. A force Fis applied on the rightmost block as shown in the figure below so that each block moves to right with acceleration a. T2 F m Applying Newton's second law on the rightmost block: ΣFx = ma Applying Newton's second law on the block at the center: EFx = |- T2 = Applying Newton's second law on the leftmost block: EFx = = ma If each block has a mass of 10 kg and is accelerating at 2 m/s2, the magnitude of the tension on the second string is T2 = N.
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