This question requires the use of a standard normal table. Let z be a standard normal random variable, find P(-1.72 < z < 1.24). Enter your answer rounded to 4 decimal places.

You may need to use the appropriate appendix table to answer this question. Given that z is a standard normal random variable, find z for each situation. (Round your answers to two decimal places.) (d) The area to the right of z is 0.1271. (e) The area to the left of z is 0.6700. (f) The area to the right of z is 0.3300.

Let Z be a standard normal random variable. Use the calculator provided, or this table, to determine the value of c. P(Zsc)=0.8888 Carry your intermediate computations to at least four decimal places. Round your answer to two decimal places.

Let Z be a standard normal random variable. Use the calculator provided, or this table, to determine the value of c. P(-csZsc) =0.9357 Carry your intermediate computations to at least four decimal places. Round your answer to two decimal places. 民

You may need to use the appropriate appendix table or technology to answer this question. z is a standard normal random variable. Find  P(z ≥ 2.12).

This question requires the use of a standard normal table. Let z be a standard normal random variable, find P(Z < -.55). Enter your answer rounded to 4 decimal places.

Use a normal approximation to find the probability of the indicated number of voters. In this​ case, assume that 122 eligible voters aged​ 18-24 are randomly selected. Suppose a previous study showed that among eligible voters aged​ 18-24, 22% of them voted. Probability that fewer than 33 voted Question content area bottom Part 1 The probability that fewer than 33 of 122 eligible voters voted is. ​(Round to four decimal places as​ needed.)

Let Z be a standard normal random variable. Determine the value of c Round your responses to at least three decimal places.   P(Z≤c)= 0.1611 Carry your intermediate computations to at least four decimal places. Round your answer to two decimal places.