This problem considers strings that can be made from the alphabet A= {‘a’, ‘b’, ‘c’}. a. Write a recursive definition for the set of strings that have at least one 'a' character. b. Write a recursive definition for the set of strings that do not start with the letter 'a'.
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A= {‘a’, ‘b’, ‘c’}.
a. Write a recursive definition for the set of strings that have at least one 'a' character.
b. Write a recursive definition for the set of strings that do not start with the letter 'a'.
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- Write a recursive function that returns a value of 1 if its string argument is apalindrome and zero otherwise.* Note that for the function parameters, you need to accommodate for the shrinkingstring, so that the string shrinks both from beginning and end after each recursive call.** Think about the simple cases or base cases. The 2 base cases have conditions thatwould return 0 and return 1 independently.For the palindrome, create a driver program. First ask the user to enter anystring through the keyboard. Then remove all the spaces and punctuations from thestring. Also, remove any letter capitalization from the string. Finally, pass the string tothe palindrome function through a function call.def height(words, word): The length of a word is easy enough to define by tallying up its characters. Taking the road less traveled, we define the height of the given word with a recursive rule for the height of the given word to follow from the heights of two words whose concatenation it is. First, any character string that is not one of the actual words automatically has zero height. Second, an actual word that cannot be broken into a concatenation of two nonempty actual words has the height of one. Otherwise, the height of an actual word equals one plus the larger of the heights of the two actual words whose combined concatenation it can be expressed as. To make these heights unambiguous for words that can be split into two non-empty subwords in multiple ways, this splitting is done the best way that produces the tallest final height. Since the list of words is known to be sorted, you can use binary search (available as the function bisect_left in the bisect module) to quickly…3. A palindrome is a sentence that contains the same sequence of letters read-ing it either forwards or backwards. A classic example is "Able was I, ere I saw Elba." Write a recursive function that detects whether a string is a palindrome. The basic idea is to check that the first and last letters of the string are the same letter; if they are, then the entire string is a palindrome if everything between those letters is a palindrome. There are a couple of special cases to check for. If either the first or last character of the string is not a letter, you can check to see if the rest of the string is a palindrome with that character removed. Also, when you compare letters, make sure that you do it in a case-insensitive way. Use your function in a program that prompts a user for a phrase and then tells whether or not it is a palindrome. Here's another classic for testing: "A man, a plan, a canal, Panama!"
- Write a recursive function to print all the permutations of a string. For example, for the string abc, the printout is:abcacbbacbcacabcba(Hint: Define the following two functions. The second function is a helper function.def displayPermuation(s):def displayPermuationHelper(s1, s2): The first function simply invokes displayPermuation(" ", s). The secondfunction uses a loop to move a character from s2 to s1 and recursively invokes t with a new s1 and s2. The base case is that s2 is empty and prints s1 to the console.)Write a test program that prompts the user to enter a string and displays all its permutations.A palindrome is a sentence that contains the same sequence of letters reading it either forwards or backwards. A classic example is '1\.ble was I, ereI saw Elba." Write a recursive function that detects whether a string is apalindrome. The basic idea is to check that the first and last letters of thestring are the same letter; if they are, then the entire string is a palindromeif everything between those letters is a palindrome.There are a couple of special cases to check for. If either the first orlast character of the string is not a letter, you can check to see if the restof the string is a palindrome with that character removed. Also, when youcompare letters, make sure that you do it in a case-insensitive way.Use your function in a program that prompts a user for a phrase andthen tells whether or not it is a palindrome. Here's another classic fortesting: '1\. man, a plan, a canal, Panama!"Indirect recursion is when function A calls function B, which in turn calls function A. is it true or false.
- For function decToBinary, write the missing parts of the recursion case. This function should return a string that stores the binary equivalent for int variable num. Example: The binary equivalent of 13 may be found by repeatedly dividing 13 by 2. So, 13 in base 2 is represented by the string "1101". Examples: decToBinary(13) -> "1101" public String decToBinary (int num) { if (num < 2) return Integer.toString(num); else return <<Missing recursive call>> + <<Missing calculation>>;}S is a set of strings recursively defined as follows. Base case: Every variable from the set {a, b, c, d, e, f} is in S. Recursive rules: If x = S and y = S, then: 1. (x + y) Є S 2. x.yЄ S Indicate which expressions are in S. ☐ (d.e.a) a+b a.b.c ☐ (a + d).eWrite a recursive function called that takes a string of single names separated by spaces and prints out all possible combinations (permutations), each combination on a new line. When the input is: Alice Bob Charlie then the output is: Alice Bob Charlie Alice Charlie Bob Bob Alice Charlie Bob Charlie Alice Charlie Alice Bob Charlie Bob Alice Here is my original code that needs to be fixed: def all_permutations(permList, nameList): # TODO: Implement method to create and output all permutations of the list of names. if nameList == len(permList) - 1: return nameList else: for x in range(permList, len(nameList)): permList[nameList], permList[x] = permList[x], permList[name_List] return all_permutations(permList, nameList + 1) permList[nameList], permList[x] = permList[x], permList[name_List] if __name__ == "main": nameList = input().split(' ') permList = [] all_permutations(permList, nameList)
- CodeW For fun X C Solved https://codeworkou... 臺亂 CodeWorkout X272: Recursion Programming Exercise: Is Reverse For function isReverse, write the two missing base case conditions. Given two strings, this function returns true if the two strings are identical, but are in reverse order. Otherwise it returns false. For example, if the inputs are "tac" and "cat", then the function should return true. Examples: isReverse("tac", "cat") -> true Your Answer: 1 public boolean isReverse(String s1, String s2) { 2. if > 3. 4. else if > return true; return false; 5. 6. else { String s1first = String s2last return s1first.equals (s2last) && 51. substring(0, 1); s2, substring(s2.length() 1); 7. 8. 6. isReverse(s1.substring(1), s2.substring(0, s2.length() 1)); { 12} 1:11AM 50°F Clear 12/4/20211. Write a recursive method expFive(n) to compute y=5^n. For instance, if n is 0, y is 1. If n is 3, then y is 125. If n is 4, then y is 625. The recursive method cannot have loops. Then write a testing program to call the recursive method. If you run your program, the results should look like this: > run RecExpTest Enter a number: 3 125 >run RecExpTest Enter a number: 3125 2. For two integers m and n, their GCD(Greatest Common Divisor) can be computed by a recursive function. Write a recursive method gcd(m,n) to find their Greatest Common Divisor. Once m is 0, the function returns n. Once n is 0, the function returns m. If neither is 0, the function can recursively calculate the Greatest Common Divisor with two smaller parameters: One is n, the second one is m mod n. Although there are other approaches to calculate Greatest Common Divisor, please follow the instructions in this question, otherwise you will not get the credit. Meaning your code needs to follow the given algorithm. Then…In C++ Write a program that lists all ways people can line up for a photo (all permutations of a list of strings). The program will read a list of one word names (until -1), and use a recursive method to create and output all possible orderings of those names, one ordering per line. When the input is: Julia Lucas Mia -1 hen the output is (must match the below ordering): Julia Lucas Mia Julia Mia Lucas Lucas Julia Mia Lucas Mia Julia Mia Julia Lucas Mia Lucas Julia #include <vector>#include <string>#include <iostream> using namespace std; // TODO: Write method to create and output all permutations of the list of names.void AllPermutations(const vector<string> &permList, const vector<string> &nameList) { } int main(int argc, char* argv[]) { vector<string> nameList; vector<string> permList; string name; // TODO: Read in a list of names; stop when -1 is read. Then call recursive method. return 0;}