this is the template to be user. Add the code here according to the question in image. in java language. public class MergeSort { ArrayList getInput(ArrayList al) { // } void getOutput(ArrayList al) { // } void merge(ArrayList al, int beg, int mid, int end) { // } void sort(ArrayList al, int beg, int end) { // } public static void main(String[] args) { // TODO Auto-generated method stub } }
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this is the template to be user. Add the code here according to the question in image. in java language.
public class MergeSort {
ArrayList getInput(ArrayList<Integer> al) { // }
void getOutput(ArrayList<Integer> al) { // }
void merge(ArrayList<Integer> al, int beg, int mid, int end) { // }
void sort(ArrayList<Integer> al, int beg, int end) { // }
public static void main(String[] args) { // TODO Auto-generated method stub }
}
Step by step
Solved in 3 steps with 4 images
- Develop an implementation of insertion sortthat moves larger elements to the right one position with one array access per entry,rather than using exch(). Use SortCompare to evaluate the effectiveness of doing so.Develop an implementation of insertion sortthat moves larger elements to the right one position with one array access per entry,rather than using exch(). Use SortCompare to evaluate the effectiveness of doing so.Using the provided MinHeap implementation & helper functions, build two sorted arrays as follows: Option 1:Given an unsorted array, build a sorted array in ascending order utilizing a minheap. Hint: this one is quite easy.. Load a minheap with your unsorted array. From there you can get the min element from the minheap & build your sorted array. Option 2:Given your unsorted array loaded into a maxheap.. Using this max-heap, in which the root node contains the largest element, build a sorted array in ascending order. To achieve this you’ll ‘Float’ the max to the front and build the sorted list from the back. The basic idea is to sort in place. - Every time the algorithm polls from the heap, the heaps size shrinks by one. - Hence, the next place at the end of the array is not part of the heap anymore. - At this index the n-th smallest number is placed. Final Solution should look like: Array to be sorted by MinHeap: [5, 3, 17, 10, 84, 19, 6, 22,…Following is the partition function for quicksort, where we have used the leftmost number as a pivot. Assume that our array, ARR = {14, 8, 7, 38, 22, 15, 9}, which is 7 in size. What will be the array ARR after we apply "partition(A, 0, 6)"* 9, 15, 22, 38, 7, 8, 14 7, 8, 9, 14, 15, 22, 38 9, 8, 14, 7, 22, 15, 38 9, 8, 7, 14, 22, 15, 38 7, 9, 15, 22, 38, 14, 6 38, 22, 15, 14, 9, 8, 7
- Using C++ Implement the ordered version of removeElement in the window below. Your function should validate inputs and remove the element in the given position by moving all of the other elements down. // removeElement preserves the order of the remaining elements in the array.// @param: char array that is ordered in some way.// @param: int numElems is the number of elements// @param: int position of the element being removed// @returns true if the element is removed, false otherwise.// be careful to use reference parameters where necessary!LANGUAGE IS C++ Assignment 6B: Forwards and Backwards. Up to this point, we have sorted array values from smallest to largest. However, there are times when we need to do the reverse and sort from largest to smallest. We will implement a way to do this using Insertion Sort and Selection Sort.Take in an initial array size value from the user (C++ students: Check the Appendix for more information on how to do this) and a value for the highest possible value in the sequence. Fill the array with random values between 0 and that highest value. Then provide the user with the following options: Change the array’s elements with new random values◦ Use the numbers entered by the user initially for this; do not prompt the user for new numbers Sort from smallest to largest◦ Use Insertion Sort to sort the array so that the smallest value is at index 0, and the largest value is at the end of the array. Sort from largest to smallest◦ Use Selection Sort to sort the array so that the largest value…Multiply left and right array sum. Basic Accuracy: 54.29% Submissions: 12630 Points: 1 Pitsy needs help in the given task by her teacher. The task is to divide a array into two sub array (left and right) containing n/2 elements each and do the sum of the subarrays and then multiply both the subarrays. Example 1: â€7. Suppose we are sorting an array of eight integers using quicksort, and we have just finished the first partitioning with the array looking like this: 25179 12 11 10 Which statement is correct? A. The pivot could be either the 7 or the 9. B. The pivot could be the 7, but it is not the 9. C. The pivot is not the 7, but it could be the 9. D. Neither the 7 nor the 9 is the pivot.Assume you have an array and a linked-list that each contain a list of 10 books. Which of the following is true? Group of answer choices 1. It is faster to access the 5th book in the array than to access the 5th book in the linked-list because arrays allow for directly accessing the appropriate spot in memory, while a linked list requires stepping through the previous 4 elements. 2. Shuffling the order of the Books in the linked-list will be easier than for the array. 3. It is faster to add a new book to the end of the linked list than to the array, because the entire array needs to be copied to a larger space in memory in order to add a new element. 4. All options are true.I hope this question will be solved in less than an hour and not taken from other sitesdata structure Given the following array: 65, 15, 129, 22, 12, 10, 239, 334, 10, 111, 180, 1, 2 What will be the array contents looking like in the following situations: 1) after calling the partition method three times in quick sort if pivot is the last element. 2) after the third iteration of the outer loop in insertion sort. 3) after the third iteration of the outer loop in Selection sort.Given an infix expression 2*3/(2-1)+5*3. Your task is to covert the givenexpression into postfix notation. The final result should be 23*21-/53*+. (Note: Make use ofstack data structure only. However the underlying implementation should be an array). Evaluatethe resultant postfix notation and show the final result. The final result should be 211.Given an array arr[] and an integer K where K is smaller than size of array, the task is to find the Kth smallest element in the given array. It is given that all array elements are distinct. Note :- l and r denotes the starting and ending index of the array. Example 1: Input: N = 6 arr[] = 7 10 4 3 20 15 K = 3 Output : 7.Rewrite this code, using modular programming style, and correcting any errors if necessary. 2. Optimize the algorithm by making the following modifications: (a) After the first pass, the largest number is guaranteed to be in the highest- numbered element in the array; after the second pass, the two highest numbers are "in place," and so on. Instead of comparing every pair on every pass, modify the algorithm to make as few comparisons as necessary on each pass. (b) Modify the algorithm to check at the end of each pass if any swaps have been made. If none have been made, the data must already be in the proper order, so the program should terminate. Observe the single-exit point rule when making this modification. 3. Insert appropriate statements in your code to output the state of the array after every pass. #include <iostream> #include <iomanip> using namespace std; using std::setw; using std::cout; using std::endl; using std::size_t; int main() { const short…SEE MORE QUESTIONS