This is a question from mechanics of material book (axial load chapter). I need the correct solution please, it is very important and answers I have seen are vary.
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- The results of a tensile test are shown in Table 1.5.2. The test was performed on a metal specimen with a circular cross section. The diameter was 3 8 inch and the gage length (The length over which the elongation is measured) was 2 inches. a. Use the data in Table 1.5.2 to produce a table of stress and strain values. b. Plot the stress-strain data and draw a best-fit curve. c. Compute the, modulus of elasticity from the initial slope of the curve. d. Estimate the yield stress.A tensile test was performed on a metal specimen with a diameter of 1 2 inch and a gage length (the length over which the elongation is measured) of 4 inches. The dam were plotted on a load-displacement graph. P vs. L. A best-fit line was drawn through the points, and the slope of the straight-line portion was calculated to be P/L =1392 kips/in. What is the modulus of elasticity?A tensile test was performed on a metal specimen having a circular cross section with a diameter 0. 510 inch. For each increment of load applied, the strain was directly determined by means of a strain gage attached to the specimen. The results are, shown in Table: 1.5.1. a. Prepare a table of stress and strain. b. Plot these data to obtain a stress-strain curve. Do not connect the data points; draw a best-fit straight line through them. c. Determine the modulus of elasticity as the slope of the best-fit line.
- An aluminum [E = 11500 ksi] control rod with a circular cross section must not stretch more than 0.21 in. when the tension in the rod is 2080 lb. If the maximum allowable normal stress in the rod is 11.5 ksi, determine: (a) the smallest diameter d that can be used for the rod. (b) the corresponding maximum length L of the rod. Answers: (a) d = i (b) L = i in. in.An aluminum rod is rigidly attached between a steel rod and a bronze as shown. Axial loads are applied at the positions indicated. Find the stress of each rod in MPa. Steel Aluminum Bronze A- 500mm A = 400mm? A- 200mm 40KN 10KN 20KN 1.5m 2.5m 2.0m Determine the change in length of steel rod having a length of 800mm and a diameter of 6.5mm. The rod is subjected to a force P equal to 110KN. Young's Modulus is 200GPA Compute normal strain of the rodA ngid bar AB is hinged at A and is supported by a rod CD at C. The rod is pin connected at D. as shown Neglect deflections of the bar due to bending Use E200 GPa What is the displacement of the loaded end of the bar? 2 Determine the tensile stress induced in rod CD by the 80 kN load the alowable stress in rod CD is 124 MPa, what weight W can be safely applied?
- 3) An bronze rod is rigidly attached between a aluminum rod and a steel rod as shown. Axial loads are applied at the positions indicated. Find the maximum allowable value of P that will not exceed a stress in steel of 140MPA, in aluminum of 90MPA or in bronze of 100MPа. Aluminum A = 500mm? Bronze A = 200mm? Steel A = 150mm2 2P ЗР L st = 1.2m L br = 2m Lal = 3.5mA typlcal aluminum-alloy scuba diving tank is shown. The outside diameter of the tank is 200 mm and the wall thickness is 12 mm. If the air In the tank is pressurized to 16MP3, determine the maximum shear stress in the plane of the cylinder wall. O 29.3 MPa O 33.7 MPa O 27.4 MPa O 40.7 MPa O 21.0 MPaAn aluminum rod is rigidly attached between a steel rod and a bronze as shown. Axial loads are applied at the positions indicated. Find the stress of each rod in MPa. Steel Aluminum Bronze A- 500mm? A = 400mm? A - 200mm 40KN 10KN 20KN 2.5m 2.0m 1.5m
- The shown plate is 60 mm thick and it is made of Magnesium Am1004-T61. The plate is fitted between the rigid frictionless supports as shown and at T, = 20°C it is stress free. Find the stresses in the x and y directions when the temperature increases to T, = 58°C. %3D 150 mm 150 mm Select one: O x: 0 MPa, y: 42.864 MPa Ox: 22.1 MPa, y: 44.2 MPa Ox: 0 MPa, y: 44.2 MPa Ox: 0 MPa, y: 17.8 MPa O x: 13.2 MPa, y: 44.2 MPa Ox: 0 MPa, y: 67.4 MPa 3:10 PM O G 4) ENG 1/31/2021Q # 4: An aluminum rod is rigidly attached between a steel rod and a bronze rod as shown in Figure. Axial loads are applied at the positions indicated. The value of P is limited to 20 KN in bronze, 72 KN in aluminum and 28 KN in steel Find the area of each section that will not exceed a stress in steel of 280 MPa, in aluminum of 180 MPa, or in bronze of 200 MPa. CLO -2 Steel Aluminum Bronze 2P 4P 2.5 2.0 1.5A rod is composed of an aluminum section rigidly attached between steel and bronze sections, as shown in the figure. Axial loads are applied at the positions indicated. If P 4000 Ib and the cross-sectional area of the rod is 1.0 sq.in. What is %3D the stress in the bronze? (in ksi) Note: indicate sign (no sign means positive/tenslon) 4P Steel Bronze Aluminum 2 ft 3 ft 2.5 ft