A ALEKS - Alec Nema - LearnG Complete the table below, which xC Complete The Table Below, Whici x+ > C OA www-awu.aleks.com/alekscgi/x/Isl.exe/1o_u-lgNslkr7j8P3jH-IvUrTNdLZh5A8CnG03PBGuXr8iCPa7ZMmym9dT1il1Gkroy7AtUHLxV9FND2YCHj_luf5tjUsCtVPrkHH_G..AppsSprouts Academy.O Online Tutoring C 400 Request Heade.Q Weather & Soil CH.O THERMOCHEMISTRYSolving combustion thermochemistry problemsAlec vOn a 10 day wilderness expedition you'll need to heat 3.0 kg of water to the boiling point each day. The air temperature will average 25 °C. You have availablecanisters of compressed propane (C,Hg) fuel, which you'll burn to heat the water. Each canister has 50. g of propane in it. What is the minimum number of fuelcanisters you must bring?The standard heat of formation of propane at 25 °C is -103.85 kJ/mol. You'll probably find other helpful data in the ALEKS Data resource.圖dlocanisters:ExliyanationCheckO 2020 McGraw-Hill Education. All Rights Reserved. Terms of Use| Privacy | Accessibility9:58 PMO Type here to search12/11/2020

We are given, The number of days: nd=10 The mass of water required every day: mw=3 kg The initial temperature of the water: Ti=25∘C The final temperature of the water:Tf=100∘C The thermal value of C3H8: ΔH=103.85 kJ/mol The mass of C3H8in each of the canisters: mp=50 g We Know, The specific heat of water: CH2O=4186 J/g∘C The molar mass of C3H8: MC3H8=44 g/molCombustion of propane is given by: Enthalpy of combustion is given by: Heat required to heat water is given by: Given that: Mass of water, m = 3 kg Specific heat capacity of water, C = 4184 J/kg.oC Change in temperature, Therefore, Heat required to heat water is given by: H=mc∆T=3 kg×4184 J/kg°C×75°C H= 941400 J We know that, heat lost by the combustion of propane is the heat gained by water to heat. Hence, No. of moles of propane burnt to heat water is given by: n=H∆H=941400 J2219.85×103 n = 0.424 We have, Molar mass of propane is 44 g/mol Therefore, Mass of propane required is given by: m= 0.424 mol x 44 g/mol m = 18.65 gm Hence, 18.65 g of propane is required in 1 day. For 10 days: M = m x 10 = 18.65 x 10 M = 186.5 Given that. Each canister contains 75 g propane. Therefore minimum no. of canisters required is given by: No. of canisters = M75 g=186.575=2.4 Rounding to highest integer: That is, minimum no. of canisters required is 3.