● ● thermal conductivity=0.627 N/(°C.s) • specific heat-c-3470 Nm/kg °C density=1100 kg/m³ 2nd: Calculate the thermal resistance (R or R₁) of human skin with a thickness of 2 cm, per cm² of skin. ● Rt = L KA where k is the materials conductivity [W.m.K] is the plane thickness [m] A is the plane area [m²]

Materials Science And Engineering Properties
1st Edition
ISBN:9781111988609
Author:Charles Gilmore
Publisher:Charles Gilmore
Chapter4: Temperature Effects On Atom Arrangements And Atom Motion
Section: Chapter Questions
Problem 4.10P
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2nd: Calculate the thermal resistance (R or R₂) of human skin with a
thickness of 2 cm, per cm² of skin.
●
thermal conductivity=0.627 N/(°C.s)
●
• specific heat-c-3470 Nm/kg °C
• density=1100 kg/m³
Rt
-
L
KA
where
k is the materials conductivity [W.m³!.K-¹]
L is the plane thickness [m]
A is the plane area [m²]
Transcribed Image Text:Questions: 2nd: Calculate the thermal resistance (R or R₂) of human skin with a thickness of 2 cm, per cm² of skin. ● thermal conductivity=0.627 N/(°C.s) ● • specific heat-c-3470 Nm/kg °C • density=1100 kg/m³ Rt - L KA where k is the materials conductivity [W.m³!.K-¹] L is the plane thickness [m] A is the plane area [m²]
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