Therefore | (A')"| = |S¯¹ A"S| |(A')"| = |S¯¹ ||S||A"|. |(A')"| = |I||A", where I is the identity matrix. Hence |(A')"| = |A"|, as |I| = 1 for any identity matrix. (A')n = S-¹AA... AS, where the A matrices are repeated n times.
Therefore | (A')"| = |S¯¹ A"S| |(A')"| = |S¯¹ ||S||A"|. |(A')"| = |I||A", where I is the identity matrix. Hence |(A')"| = |A"|, as |I| = 1 for any identity matrix. (A')n = S-¹AA... AS, where the A matrices are repeated n times.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![|(A')"| = |S¯¹ ||A"||S|, where we have
used |AB| = |A||B|.
(A')n = S-¹A¹S
(A')n = [S¹ AS][S¯¹ AS] ... [S¹ AS]
where the terms in square brackets are
repeated n times.
|(A')"| = |S¯¹S||A", where we have
used |AB| = |A||B|.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3b765a29-fcb0-4895-9cef-5ef60c256f5b%2F889c4ba4-8657-4602-bce0-982e4980caf3%2Fcebtwv_processed.png&w=3840&q=75)
Transcribed Image Text:|(A')"| = |S¯¹ ||A"||S|, where we have
used |AB| = |A||B|.
(A')n = S-¹A¹S
(A')n = [S¹ AS][S¯¹ AS] ... [S¹ AS]
where the terms in square brackets are
repeated n times.
|(A')"| = |S¯¹S||A", where we have
used |AB| = |A||B|.
![Therefore |(A')"| = |S¯¹ A"S|
|(A')"| = |S¹||S||A"|.
|(A')"| = |I||A", where I is the identity
matrix.
Hence |(A')"| = |A"|, as |I| = 1 for any
identity matrix.
(A')¹ = S-¹ AA ... AS, where the A
matrices are repeated n times.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3b765a29-fcb0-4895-9cef-5ef60c256f5b%2F889c4ba4-8657-4602-bce0-982e4980caf3%2Flyfgcg_processed.png&w=3840&q=75)
Transcribed Image Text:Therefore |(A')"| = |S¯¹ A"S|
|(A')"| = |S¹||S||A"|.
|(A')"| = |I||A", where I is the identity
matrix.
Hence |(A')"| = |A"|, as |I| = 1 for any
identity matrix.
(A')¹ = S-¹ AA ... AS, where the A
matrices are repeated n times.
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