Thereaction time of the average motorist is 0.70 s. Assume that by means of the brakes, a retarding force equal to three-fourths the weight of the car can be applied to the car. If the car is travelling 60 mi/h find: a.The acceleration when the brakes are applied and b.The distance the car travels after the motorist receives the stopping signal

At time t = 0, a car has a velocity of 16 m/s. The brakes are applied so the car decelerates at 2 m/s2. The car will stop after:

A basketball player jumps straight up for a ball. To do this he lowers his body 0.28 m then accelerates through this distance b forcelly straightening his legs. This player leaves the floor with a vertical velocity sufficient to carry him 0.92 m above the floor. For this problem use a coordinate system where up is positive. A) Calculate his velocity when he leaves the floor in m/s B) Calculate his acceleration in m/s2, while he is straightening his legs.He goes from zero to the velocity found in part(a) in a distance of 0.28 m C) Calculate the magnitude of the force he exerts on the floor to do this, in newtons, given that his mass is 112kg

An object accelerates at 4m/s2 due to a 20N force applied to it. (a) What amount of force is needed to produce an acceleration of 2.0 m/s2 to the same object? (b) What amount of force is needed to produce an accelaration of 12m/s2 to the same object?   I ALREADY NEED IT PLEASE ANSWER?