There is an arrangement of three charges distributed along a perimeter of a circumference, the charge q1, is located at the point r1 = r with an angle of 90 o, q2, is located at the point r2 = r with an angle of 150 o, q3, is located at the point r3 = r with an angle of 300. Calculate the electric force on charge q3. Consider that the charges q1, q2 and q3 are equal to q. Se tiene un arreglo de tres cargas distribuidas a lo largo de un perímetro de una circunferencia, la carga q1, se localiza en el punto r; =r con unángulo de 90°, q2, se localiza en el punto rz2 = r con un ángulo de 150°, q3, se localiza en el punto r3 = r con un ángulo de 30°. Calcule la fuerzaeléctrica sobre la carga q3. Considere que las cargas q1, 92 y q3, son iguales a q.O a. F3 = [ (k q)/(r²) ] [ (1/6)(3v3) i – (1/2) j ] NO b. F3 = [- (k q²)/(r2) ] [ (1/6)(3v3) i + (1/ 2) j] NO. F3 = [- (k q/(12) ] [ (1/2) iO d. F3 = [ (k q?)/(r2) ] [ (1/2) i – (1/6)(3v3) j] NO e. F3 = [-(k q)/(r) ] [ (1/2) i – (1/6)(3v3) j] N%3DOb.+ (1/6)(3v3) j] N%3D%3D

Choose the correct, Find the electric field at the point Q3. F3?

Answered: There is an arrangement of three…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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There is an arrangement of three charges distributed along a perimeter of a circumference, the charge q₁, is located at the point r₁ = r with an angle of 90 ^o, q₂, is located at the point r₂ = r with an angle of 150 ^o, q₃, is located at the point r₃ = r with an angle of 30⁰. Calculate the electric force on charge q3. Consider that the charges q1, q2 and q3 are equal to q.

Se tiene un arreglo de tres cargas distribuidas a lo largo de un perímetro de una circunferencia, la carga q1, se localiza en el punto r; =r con un
ángulo de 90°, q2, se localiza en el punto rz2 = r con un ángulo de 150°, q3, se localiza en el punto r3 = r con un ángulo de 30°. Calcule la fuerza
eléctrica sobre la carga q3. Considere que las cargas q1, 92 y q3, son iguales a q.
O a. F3 = [ (k q)/(r²) ] [ (1/6)(3v3) i – (1/2) j ] N
O b. F3 = [- (k q²)/(r2) ] [ (1/6)(3v3) i + (1/ 2) j] N
O. F3 = [- (k q/(12) ] [ (1/2) i
O d. F3 = [ (k q?)/(r2) ] [ (1/2) i – (1/6)(3v3) j] N
O e. F3 = [-(k q)/(r) ] [ (1/2) i – (1/6)(3v3) j] N
%3D
Ob.
+ (1/6)(3v3) j] N
%3D
%3D

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