
Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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How do you ensure there is always at least one primary key if you believe a relation has no duplicate data?
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- Please help with the folllowing: Consider the following declaration of a relation schema CREATE TABLE R ( A int PRIMARY KEY, B int not null, C char (1) ); Then execution of which of the following queries will fail? QI: Insert INTO R (B, C) Values (353, 'B'); Q2: Insert INTO R (A, C) Values (111, ‘A’); Q3: Insert INTO R (A, B) Values (222, 335); Select one: a. Both QI and Q2 b. QI only c. Both QI and Q3 d. Q2 onlyarrow_forwardImplement a new independent entity phone in the Sakila database. Attributes and relationships are shown in the following diagram: The diagram uses Sakila naming conventions. Follow the Sakila conventions for your table and column names: All lower case Underscore separator between root and suffix Foreign keys have the same name as referenced primary key Write CREATE TABLE and ALTER TABLE statements that: Implement the entity as a new phone table. Implement the has relationships as foreign keys in the Sakila customer, staff, and store tables. Remove the existing phone column from the Sakila address table. Step 2 requires adding a foreign key constraint to an existing table. Ex: ALTER TABLE customer ADD FOREIGN KEY (phone_id) REFERENCES phone(phone_id) ON DELETE SET NULL ON UPDATE CASCADE; Specify data types as follows: phone_id, phone_number, and country_code have data type INT. phone_type has date type VARCHAR(12) and contains strings like 'Home', 'Mobile', and 'Other'. Apply…arrow_forward(Choose all of the correct superkeys.) Find all superkeys of the DEPARTMENT relation. Its primary key (PK) is underlined. DEPARTMENT (number, dname, mgrssn, location) PK = {dname, location} {number} {number, dname} {number, dname, mgrssn} {number, dname, mgrssn, location} {dname} {dname, mgrssn} {dname, mgrssn, location} {mgrssn} {mgrssn, location} {location} {number, dname, mgrssn} {number, dname, location} {number, mgrssn} {number, mgrssn, location} {number, location} {dname, location}arrow_forward
- What is the purpose of denormalization? Whymight you not want to create one physical tableor file for each relation in a logical data model?arrow_forwardconvert it to relations that are normalizationarrow_forwardRun the problem using Relational Algebra, below the problem I added the needed table. Use self join find the answer (4) Find the name (fname,lname) of the direct supervisor of “Mary Smith”. (“Mary Smith” is an employee). group: emplyeeemployee = {fname, lname, ssn,superssn, departnumber'Mary', 'Smith',111, 222, 11'Green', 'Marjorie',333, 222, 12'Gren', 'Cheryl',222, 777, 14}arrow_forward
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