There is a shape at the centre of the structure from the floor to the roof. Below is the position of the x and y coordinates. (a) (b) (c) (d) Position 1 2 3 4 5 5 to 1 (f) x coordinate y coordinate B 0 B A - B A - B 0 0 - B A quarter-circle: x² + y² = B² Present the shape by joining all points in FOUR straight lines and ONE quarter-circle. Write down the equation for the FOUR straight lines and ONE quarter-circle. Double Integral Determine the value of the upper and lower limits of x1, x2, yl, and y2. Find the volume of the pillar and explain the working steps. ry2 y1 x2 m² Change Order of Double Integral Determine the value of the upper and lower limits of x3, x4, y3, and y4. Find the volume of the pillar and explain the working steps. cx4 y4 * *z(x, y) dy dx x3 y3 MATLAB or OCTAVE Method (e) Find the pillar volume by using MATLAB or OCTAVE (integral2 function). Use those limits stated in part 2(c). y2 z(x,y) dx dy y1 x2 * x1 z(x,y) dx dy Comments on the results for part 2(c), 2(d), and 2(e).

2x-67=48

where did you get 16 from ?

w2=-8w-19

et △ABC be a triangle in S^2 (the two-dimensional sphere). Let the dual point C'∈S^2 of C be defined by the following three conditions:(i) d(C' , A)=π/2(ii) d(C' , B)=π/2(iii) d(C' , C)≤π/2A' and B' are defined analogously. Thus we get a dual triangle △A' B' C'. More precisely, △ABC is a non-degenerate triangle, andit follows (you may assume) that △A' B' C' is too.(question) Are there triangles △ABC in S^2 identical to their own dual △A'B'C'?   I would be very thankful if you could provide some explanation with the steps, thank you in advance.