There are 3 mass hangers with masses attached to the central ring via these strings such that the net force acting on the ring is zero. Write down individual total masses in kilograms, the angle that they are directed at using the inner angles. Magnitude of the sum of the forces due to string 1 and 2 = String Number Mass Attached (kg) Force Exerted (N) Direction (°) 1 .25 2.45 30° 2 .25 3.45 120° 3 .35 3.43 255°
There are 3 mass hangers with masses attached to the central ring via these strings such that the net force acting on the ring is zero. Write down individual total masses in kilograms, the angle that they are directed at using the inner angles. Magnitude of the sum of the forces due to string 1 and 2 = String Number Mass Attached (kg) Force Exerted (N) Direction (°) 1 .25 2.45 30° 2 .25 3.45 120° 3 .35 3.43 255°
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There are 3 mass hangers with masses attached to the central ring via these strings such that the net force acting on the ring is zero. Write down individual total masses in kilograms, the angle that they are directed at using the inner angles.
Magnitude of the sum of the forces due to string 1 and 2 =
| String Number | Mass Attached (kg) | Force Exerted (N) | Direction (°) |
| 1 | .25 | 2.45 | 30° |
| 2 | .25 | 3.45 | 120° |
| 3 | .35 | 3.43 | 255° |
Transcribed Image Text:80
70 60
50
12
09
1
120 130
06
10
20 30 40
40
Forc
ble
eisco
00 200 210 22O 230
120 130 1 40 150 160 170,
300 310 320 330 340 350
50 40 3p 20 10
Transcribed Image Text:For
3.
eiscO
#1: 250 g
# 2: 250 g
# 3: 350 g
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