MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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The​ quality-control manager at a compact fluorescent light bulb​ (CFL) factory needs to determine whether the population mean life of a large shipment of CFLs is equal to​ 7,497 hours. The population standard deviation is​ 1,080 hours. A random sample of 81 light bulbs indicates a sample mean life of​ 7,197 hours.
 
a. Let μ be the population mean. Determine the null​ hypothesis, H0​, and the alternative​ hypothesis, H1.
                  A. H0 : μ = 7,197 and H1 : μ ≠ 7,197, because the sample mean is always used in hypothesis testing
                  B. H0 : μ = 7,497 and H1 : X = 7,197, because the population mean is used in H0 and the sample                         mean           in H1
                 C. H0 : μ ≠ 7,497 and H1 : μ = 7,497​, because H0 never uses the equal symbol
                 D. H0 : μ = 7,497 and H1 : μ ≠ 7,497 because the​ "goal" or​ "historical data" is always used when stating              the hypotheses
 
What is the value of the test statistic? ​(Round to two decimal places to the right of the decimal point as​ needed.)
 
 
See fig 1.
 
What​ is/are the critical​ value(s)? ​(Round to two decimal places to the right of the decimal point as needed. Use a comma to separate answers as​ needed.)
A. ​-1.96 and​ +1.96 found using±​NORM.S.INV(0.05/2)
B.​-1.96 found using​ (NORM.S.INV(0.05/2)
C.​+1.96 found using​ -(NORM.S.INV(0.05/2))
D.​-1.64 and​ +1.64 found using±​NORM.S.INV(0.05)
 
What is the final​ conclusion?
 
A. Fail to reject H0. There is sufficient evidence to prove that the mean life is different from​ 7,497 hours.
B. Fail to reject H0. There is not sufficient evidence to prove that the mean life is different from​ 7,497 hours.
C. Reject H0. There is sufficient evidence to prove that the mean life is different from​ 7,497 hours.
D. Reject H0. There is not sufficient evidence to prove that the mean life is different from​ 7,497 hours.
 
b. What is the​ p-value? ​(Round to three decimal places to the right of the decimal point as​ needed.)
Interpret the meaning of the​ p-value. Choose the correct answer below.
 
A. Fail to reject H0. There is sufficient evidence to prove that the mean life is different from​ 7,497 hours.
B. Reject H0. There is sufficient evidence to prove that the mean life is different from​ 7,497 hours.
C. Reject H0. There is not sufficient evidence to prove that the mean life is different from​ 7,497 hours.
D. Fail to reject H0. There is not sufficient evidence to prove that the mean life is different from​ 7,497 hours.
 
c. Construct a​ 95% confidence interval estimate of the population mean life of the light bulbs.  ​(Round to one decimal place as​ needed.)
A. 6,961.8 ≤ μ ≤ 7,432.2​, found using​ 7,197± ​CONFIDENCE.NORM(0.05,1080,81)
B. 7,261.8 ≤ μ ≤ 7,732.2​, found using​ 7,497±​CONFIDENCE.NORM(0.05,1080,81)
C. 6,928.0 ≤ μ ≤ 7,466.0​, found using​ 7,197±​CONFIDENCE.NORM(0.05/2,1080,81)
D. 7,170.9 ≤ μ ≤ 7,223.1​, found using​ 7,197±CONFIDENCE.NORM(0.05,120,81)
 
d. Compare the results of​ (a) and​ (c). What conclusions do you​ reach?
A.The results of​ (a) and​ (c) are not the same: there is not sufficient evidence to prove that the mean life is different from​ 7,497 hours.
B.The results of​ (a) and​ (c) are not the​ same: there is sufficient evidence to prove that the mean life is different from​ 7,497 hours.
C.The results of​ (a) and​ (c) are the​ same: there is not sufficient evidence to prove that the mean life is different from​ 7,497 hours.
D.The results of​ (a) and​ (c) are the​ same: there is sufficient evidence to prove that the mean life is different from​ 7,497 hours.
A.
B.
O C.
O D.
ZSTAT
ZSTAT
ZSTAT
ZSTAT
= +2.50, found by
=
=
=
+0.28, found by
- 2.50, found by
-0.28, found by
(7497 - 7197)
1080
√81
(7497 - 7197)
(1080)
(7197 - 7497)
1080
√81
(7197 - 7497)
(1080)
= + 2.50
= +0.28
=
- 2.50
= -0.28
expand button
Transcribed Image Text:A. B. O C. O D. ZSTAT ZSTAT ZSTAT ZSTAT = +2.50, found by = = = +0.28, found by - 2.50, found by -0.28, found by (7497 - 7197) 1080 √81 (7497 - 7197) (1080) (7197 - 7497) 1080 √81 (7197 - 7497) (1080) = + 2.50 = +0.28 = - 2.50 = -0.28
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