Theorem 6.9. Let A be a compact subspace of a Hausdorff space X. Then A is closed.

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How do I show 6.9? Please explain with great detail.

Theorem 6.9. Let A be a compact subspace of a Hausdorff space X. Then A is closed.
Definition. Let A be a subset of X and let C
Then C is a cover of A if and only if A c Urea
of A if and only if C is a cover of A and each Ca is open. A subcover C' of a cover C of
A is a subcollection of C whose elements form a cover of A.
{Ca}a€a be a collection of subsets of X.
Ca. The collection C is an open cover
For instance, the open sets {(-n, n)}nen form an open cover of R. A subcover of
this cover is {(-n, n)}n>5, because these sets still cover all of R.
Definition. A space X is compact if and only if every open cover of X has a finite
subcover.
Definition. A collection of sets has the finite intersection property if and only if
every finite subcollection has a non-empty intersection.
Transcribed Image Text:Theorem 6.9. Let A be a compact subspace of a Hausdorff space X. Then A is closed. Definition. Let A be a subset of X and let C Then C is a cover of A if and only if A c Urea of A if and only if C is a cover of A and each Ca is open. A subcover C' of a cover C of A is a subcollection of C whose elements form a cover of A. {Ca}a€a be a collection of subsets of X. Ca. The collection C is an open cover For instance, the open sets {(-n, n)}nen form an open cover of R. A subcover of this cover is {(-n, n)}n>5, because these sets still cover all of R. Definition. A space X is compact if and only if every open cover of X has a finite subcover. Definition. A collection of sets has the finite intersection property if and only if every finite subcollection has a non-empty intersection.
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