The E° value for the following reaction is 0.446 V relative to the standard hydrogen electrode (SHE):   Ag2CrO4(s) + 2e-  2Ag(s) + CrO42-(aq) A chemist wishes to determine the concentration of CrO42- electrochemically. A cell is constructed consisting of a saturated calomel electrode (SCE; which has a reduction potential of 0.242 V relative to the SHE) and a silver wire coated with Ag2CrO4 and suspended in a CrO42- solution. Answer the following: (a) What is the potential of this cell at 25°C when [CrO42-] = 4.20×10-7 M? (b) For a solution of unknown [CrO42-], the measured potential for the cell at 25°C is 0.523 V. What is [CrO42-] (in mol/L)?

Cell Potential For a given galvanic cell, the standard cell potential can be calculated by subtracting the standard half-cell potential of the reaction that occurs at the cathode from the standard half-cell potential of the reaction that occurs at the anode: Ecell Ered (cathode) - Ed (anode) ▼ Tarnish on copper is the compound CuO. A tarnished copper plate i placed in an aluminum pan of boiling water. When enough salt is added so that the solution conducts electricity, the tarnish disappears. Imagine that the two halves of this redox reaction were separated and connected with a wire and a salt bridge. Part A Calculate the standard cell potential given the following standard reduction potentials: A²+ +3e Cu²+ + 20 Express your answer to two decimal places and include the appropriate units. ▸ View Available Hint(s) Ecell = li Value 4 → Units ? Al; E Cu; E 19 of 42 -1.66 V 0.340 V Review | Constants | Periodic Table

A voltaic cell is constructed in which the following cell reaction occurs. The half-cell compartments are connected by a salt bridge. Pb2+(aq) + Mn(s) Pb(s) + Mn2+(aq) The anode reaction is: The cathode reaction is: + + In the external circuit, electrons migrate e the Mn|Mn2+ electrode e the Pb|Pb2+ electrode. In the salt bridge, anions migrate e the Pb|Pb²+ compartment e the Mn|Mn2+ compartment. +

For the voltaic cell described by the cell reaction below, (1) write the cell diagram, (2) identify which specie is being reduced and which is being oxidized, (3) identify the anode and the cathode, (4) calculate the values of Q, and (5) using the table of standard reduction potentials, show the calculation of the Ecell using the Nernst equation [Ecell = E0cell – (0.0592/n x log Q)]. Zn  +  Ni+2 (0.10 M)  →  Zn+2 (0.30 M)  +  Ni

What is the voltage of the following cell? Use the Reduction Potential Table found in Chapter 17 notes. Cr(s)|Cr³*(0.25 M) || |2(s)|1-(0.20 M)|Pt(s)

A galvanic cell using Cu"/Cu and Cu?+/Cu was set up at 293 K and the non-standard cell potential was determined to be 0.175 V. Determine the concentration of ions in the cathode's solution if the concentration at the anode is 0.7787 M: (cathode)(M) number (rtol=0.03, atol=1e-08)

A voltaic cell is constructed in which the anode is a Mg|Mg2+ half cell and the cathode is a Pb/Pb2+ half cell. The half-cell compartments are connected by a salt bridge. (Use the lowest possible coefficients. Be sure to specify states such as (aq) or (s). If a box is not needed, leave it blank.) The anode reaction is: + The cathode reaction is: + The net cell reaction is: + In the external circuit, electrons migrate ✓the Pb|Pb2+ electrode In the salt bridge, anions migrate + from to ✓the Mg|Mg2+ compartment Enter electrons as e. the Mg|Mg2+ electrode. ✓the Pb|Pb²+ compartment.

Predict the products at the anode and the cathode obtained from electrolysis of a 1 M Znl2 solution. Note that 2 H20(1) + 2e → H2(g) + 2 OH(aq) E°red = -0.83 V O2(g) + 4 H*(aq) + 4e¯ → 2 H20(1) I2(s) + 2e → 2 I'(aq) Zn2*(aq) + 2e* → Zn(s) E°re = +1.23 V red E°red = +0.54 V E°, -0.76 V red = (Show work for full or partial credit.) The product at the anode is 12(s). The product at the cathode is Zn(s). The product at the anode is O2(g) and H*(aq). The product at the cathode is Zn(s). None of these The product at the anode is Zn(s). The product at the cathode is O2lg) and H*(aq). The product at the anode is O2lg) and H*(aq). The products at the cathode are H2(g) and OH (aq). The products at the anode are H2(g) and OH"(aq). The product at the cathode is O2(g) and H*(aq). The product at the anode is Zn(s). The product at the cathode is I2(s).

A lithium battery is being developed. Its voltaic cell is constructed based on Li metal electrode and PbsO4 solid electrode. Their standard reduction potentials at 25 °C are given below. E°(Li* (aq) → Li (s)) = -3.040 Volt E°(PbSO4 (S) > Pb (s) + SO42 (aq) = - 0.356 Volt. Which of the following statements is true about this working (spontaneous) voltaic cell? a. The anode is PbsO4 (s) electrode. The standard cell potential of this voltaic cell is E°(cell) = 2.328 Volt O. PBSO4 (s) is a weaker oxidizing agent than Lit. To make a commercial product, the voltaic cell is adjusted to have [Lit] = 2.1 M and [SO42] = 3.5 M. The cell d. potential E under this condition should be less than the standard cell potential E°(cell). e. None of the above