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The second page is an example how it suppose to be done.
(Hex-4-en-3-one+CH3CH2MgBR). It's complete. Please follow directions.
Step by step
Solved in 2 steps with 1 images
- tt. butanamide + methanol with acid 1. React the carbonyl compound: It is (circle one) CONJUGATED NON-CONJUGATED The Nucleophile is Potential to Establish a Resonance System Option 1: Almost all reactions Option 2 When Nu is a strong base (OH or OR), 1 (Preferred) and the leaving group is identical to the Nu NUB Circle the option and reason Option 1: Always use UNLESS Option 2: (Remove the a H) The Nu matches Y AND is -OR 2. Take care of the negative formal charge of the oxygen in the tetrahedral complex Option 1 (Preferred): All cases except Option 2 1 (Preferred) Option 2: If there are no leaving groups, R- or if the only potential leaving group is the Nu that was just added and it is not a very good leaving group (N or O). Circle the option and reason Option 1: Always use UNLESS Option 2: There is no leaving group (there are only carbons and hydrogens), OR there are only carbons and hydrogens except for the Nu that just added, AND the Nu is N or O. If the double bond is reformed,…Electron pairs CH3 .. Erase H3C - С — СІ: H3C – S- CH3 CH3 CH, CH3 THF/H,0 + H,C--CH, CH C- CH CHs CH, Use curved arrows to write the first step of this nucleophilic substitution mechanism. :ö: | :ö:2. Draw the structures and explain why CH3CH₂O and CH3CO₂ are good nucleophiles but CH3SO3, water, and alcohols (R-OH) are poor nucleophiles. Propose a 'cutoff' for the amount of negative charge needed to be a good nucleophile. CH3CH₂O CH3CO₂ CH3SO3 H₂O CH₂OH
- nn. propionaldehyde + NaOH 1. React the carbonyl compound: It is (circle one) CONJUGATED NON-CONJUGATED The Nucleophile is Potential to Establish a Resonance System :0 8- Option 1: Almost all reactions Option 2: When Nu is a strong base (OH or OR), 1 (Preferred) and the leaving group is identical to the Nu 2 NUB Circle the option and reason Option 1: Always use UNLESS Option 2: (Remove the a H) The Nu matches Y AND is -OR 2. Take care of the negative formal charge of the oxygen in the tetrahedral complex Option 1 (Preferred): All cases except Option 2 1 (Preferred) Option 2: If there are no leaving groups, or if the only potential leaving group is the Nu that was just added and it is not a very good leaving group (N or O). Circle the option and reason Option 1: Always use UNLESS Option 2: There is no leaving group (there are only carbons and hydrogens), OR there are only carbons and hydrogens except for the Nu that just added, AND the Nu is N or O. If the double bond is reformed, what…4. ) Rank the nucleophiles from weakest to strongest. (1 = weakest, 3 = strongest) %3D HO,2. H3O* Show the curved-arrow mechanism for the Claisen condensation of ethyl ethanoate treated with ethoxide ion. Include all formal charges and nonbonding electrons. In each step, draw only the species that react in that step. If an enolate resonance form is possible, draw only the carbanionic form. If a CH, group is being deprotonated, draw all H's on the reacting site. Tip: always omit ethanol byproducts. Step 1. Add curved arrows. Select Draw Rings More Erase :0 : H. H H H H
- b. On the left-hand (reactants) side of the reaction, provide the curved arrows (using the formalism you've learned in this course) necessary to form the products shown. d a. H-Ö: H-ö. H :0: 0-CH3 H. :0-CH3 H-Ö-0-H 7- Y C. :0-CH; H-0-0-HDetermine the mechanism of nucleophilic substitution of each reaction and draw the products, including stereochemistr CH₂CH3 CI Br + CN d. + CH3COOH a. acetone + -OCH3 e. DMF f. b. C. ||||| a ||||| Br H Br CH2CH2CH3 + CH3OH DMSO H CH3 CI Br + OCH₂CH3 + CH3CH₂OHPredict the product of this E2 elimination reaction. ||| Brill.... H3C Ph Ph H3C Ph Ph Ph CH3 || reaction H3C Ph IV CH3 NaOCH3 Ph H3C Bril... Ph CH3 Ph CH₂ Ph
- a. The reaction shown takes place in four steps. Complete the mechanism by adding curved arrows for each step and drawing the structures of the intermediates in the boxes. Add any missing lone pairs that are involved in the mechanism and show all nonzero formal charges. b. What kind of reaction (SN1, E1, SN2, E2) is this? [H,SO.] heat H-ö-Hited Draw both resonance structures of the most stable carbocation intermediate in the reaction shown. od m... • You do not have to consider stereochemistry. . Do not include anionic counter-ions, e.g., I', in your answer. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom Separate resonance structures using the → symbol from the drop-down menu. ● CH4 + ? HBrThe carbocation intermediate formed in the first step is resonance-stabilized. Draw the other resonance structure (by modifying the provided drawing) and add curved arrow(s) to convert the first resonance structure into the second one. Use the +/- tools to add/remove charges, and use the single bond tool to interconvert between double and single bonds. ÇH3 CH3 H3C. H,C. CH3 CH3 ČH3 ČH3 ČH3 ČH3 Edit Drawing