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The Z-transform of the following signal is: (-) 37 a [n] = 6 1 sin %3D 4.73Z-1 1+0.615Z-1 +0.25Z-2 %3D 5.71Z-1 X (3) = %3D 1-0.95Z-1+ 0.25Z-2 -1.85Z-1 X (2) =D= %3D 1 0.951Z-1 +0.25Z-2 2.85Z-1 X (2) 3= %3D 1+0.31Z-1+0.25Z-2

The Z-transform of the following signal is: (-) 37 a [n] = 6 1 sin %3D 4.73Z-1 1+0.615Z-1 +0.25Z-2 %3D 5.71Z-1 X (3) = %3D 1-0.95Z-1+ 0.25Z-2 -1.85Z-1 X (2) =D= %3D 1 0.951Z-1 +0.25Z-2 2.85Z-1 X (2) 3= %3D 1+0.31Z-1+0.25Z-2

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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The Z-transform of the following signal is: z [n] = 6 ;) sin X (x) = 4.73Z-1 1+0.615Z-1 +0.25Z-2 5.71Z-1 X (2) = 1-0.95Z-1+0.25Z-2 -1.85Z-1 %3D 1 0.951Z-1+ 0.25Z-2 2.85Z-1 X (2) = 1+0.31Z-1+ 0.25Z-2
Transcribed Image Text:The Z-transform of the following signal is: z [n] = 6 ;) sin X (x) = 4.73Z-1 1+0.615Z-1 +0.25Z-2 5.71Z-1 X (2) = 1-0.95Z-1+0.25Z-2 -1.85Z-1 %3D 1 0.951Z-1+ 0.25Z-2 2.85Z-1 X (2) = 1+0.31Z-1+ 0.25Z-2
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