The work function of lithium is 2.5 eV. The maximum wavelength of light that can cause the photoelectric effect in lithium is ______________ a) 3980 Å b) 4980 Å c) 5980 Å d) 6980 Å

0.2 eV 0.9 eV 1.1 eV A metal with a work function of 3.5 electron volts is exposed to photons of energy 3.7 electron volts. What is the maximum kinetic energy of the emitted photoelectrons? 7.7 eV

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Light with a single wavelength of 490 nm impacts a metal surface releasing an electrons.  How much energy in Joules is in each photo of this light? ________ What is the energy in eV of a photon whose wavelength is 490 nm?________ Light with a single wavelength of 490 nm impacts a metal surface releasing an electrons.  If the released electrons each have an energy of 1.9 eV, what is the work function of the metal in eV? _____ f the light source were brought closer to the surface so that the light reaching the surface was brighter which would change? ______

Light with a wavelength of 550 nm illuminates a metallic surface with a work function of 1.10 eV.        a. What is the maximum speed of the photoelectron?      b. What is the minimum potential difference required to stop the electrons?          *I ask that the answer be written with clear and readable handwriting or typed*

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The work function of cesium is 2.1 eV. ▾ Part A Determine the lowest frequency photon that can eject an electron from cesium. Express your answer with the appropriate units. Templates Symbols undo' rego Teset keyboard shortcuts Help Value Units Request Answer Part B Determine the maximum possible kinetic energy in electron volts of a photoelectron ejected from the metal that absorbs a 320-nm photon. Express your answer in electronvolts. Templates Symbols undo' redo Teset keyboard shortcuts Help Kmax= eV f= Submit