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The weight of an energy bar is approximately normally distributed with a mean of 42.35 grams with a standard deviation of 0.035 gram. Complete parts (a) through (e) below. c. If a sample of 25 energy bars is selected, what is the probability that the sample mean weight is less than 42.325 grams? 0.0001 (Round to three decimal places as needed.) d. Explain the difference in the results of (a) and (c). Part (a) refers to an individual bar, which can be thought of as a sample with sample size Therefore, the standard error of the mean for an individual bar is times the standard error of the sampl sample size 25. This leads to a probability in part (a) that (Type integers or decimals. Do not round.) V the probability in part (c). e. Explain the difference in the results of (b) and (c. The sample size in (c) is greater than the sample size in (b), so the standard error of the mean (or the standard deviation of the sampling distribution) in (c) is than in (b). As the standard error Vwhen the sample size increa values become more concentrated around the mean. Therefore, the probability that the sample mean will fall close to the population mean will always

The weight of an energy bar is approximately normally distributed with a mean of 42.35 grams with a standard deviation of 0.035 gram. Complete parts (a) through (e) below. c. If a sample of 25 energy bars is selected, what is the probability that the sample mean weight is less than 42.325 grams? 0.0001 (Round to three decimal places as needed.) d. Explain the difference in the results of (a) and (c). Part (a) refers to an individual bar, which can be thought of as a sample with sample size Therefore, the standard error of the mean for an individual bar is times the standard error of the sampl sample size 25. This leads to a probability in part (a) that (Type integers or decimals. Do not round.) V the probability in part (c). e. Explain the difference in the results of (b) and (c. The sample size in (c) is greater than the sample size in (b), so the standard error of the mean (or the standard deviation of the sampling distribution) in (c) is than in (b). As the standard error Vwhen the sample size increa values become more concentrated around the mean. Therefore, the probability that the sample mean will fall close to the population mean will always

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section: Chapter Questions
Problem 22SGR
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Previous question The weight of an energy bar is approximately normally distributed with a mean of 42.35 grams with a standard deviation of 0.035 gram. Complete parts (a) through (e) below. c. If a sample of 25 energy bars is selected, what is the probability that the sample mean weight is less than 42.325 grams? 0.0001 (Round to three decimal places as needed.) d. Explain the difference in the results of (a) and (c). Part (a) refers to an individual bar, which can be thought of as a sample with sample size . Therefore, the standard eror of the mean for an individual bar is times the standard error of the sample in (c sample size 25. This leads to a probability in part (a) that is V the probability in part (c). (Type integers or decimals. Do not round.) e. Explain the difference in the results of (b) and (c). The sample size in (c) is greater than the sample size in (b), so the standard error of the mean (or the standard deviation of the sampling distribution) in (c) is than in (b). As the standard error V values become more concentrated around the mean. Therefore, the probability that the sample mean will fall close to the population mean will always V when the sample size increases. (81) More View instructor tip Help me solve this Get more help- Next 9:19 PM 66°F P Type here to search 4/4/2022 241 144 %23 %23 24 %6 & 21 3. 4. W R Y.
Transcribed Image Text:Previous question The weight of an energy bar is approximately normally distributed with a mean of 42.35 grams with a standard deviation of 0.035 gram. Complete parts (a) through (e) below. c. If a sample of 25 energy bars is selected, what is the probability that the sample mean weight is less than 42.325 grams? 0.0001 (Round to three decimal places as needed.) d. Explain the difference in the results of (a) and (c). Part (a) refers to an individual bar, which can be thought of as a sample with sample size . Therefore, the standard eror of the mean for an individual bar is times the standard error of the sample in (c sample size 25. This leads to a probability in part (a) that is V the probability in part (c). (Type integers or decimals. Do not round.) e. Explain the difference in the results of (b) and (c). The sample size in (c) is greater than the sample size in (b), so the standard error of the mean (or the standard deviation of the sampling distribution) in (c) is than in (b). As the standard error V values become more concentrated around the mean. Therefore, the probability that the sample mean will fall close to the population mean will always V when the sample size increases. (81) More View instructor tip Help me solve this Get more help- Next 9:19 PM 66°F P Type here to search 4/4/2022 241 144 %23 %23 24 %6 & 21 3. 4. W R Y.
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