The weight and volume of a fully saturated soil sample were 55.4 g and 29. 2 cm3 respectively. After drying in an oven for 24 hours, its weight and volume reduced to 39.8 g and 21.1 cm3 respectively. Find out the shrinkage limit of the soil. a. 18.8% b. 14.4% c. 16.6% d. 12.2%

The weight and volume of a fully saturated soil sample were 55.4 g and 29. 2 cm3 respectively. After drying in an oven for 24 hours, its weight and volume reduced to 39.8 g and 21.1 cm3 respectively. Find out the shrinkage limit of the soil. a. 18.8% b. 14.4% c. 16.6% d. 12.2%

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter4: Plasticity And Structure Of Soil

Section: Chapter Questions

Problem 4.12P

See similar textbooks

Related questions

Q: rface and it is

A: soapy patches option D is correct answer

Q: The plate as shown weighing 25 kN is raised by a cable sling. The cable sling has the identical clev...

Q: A tri metallic bar is uniformly compressed by appl through a rigid end plate The bar consists of a c...

Q: - 24 in.-20 in.→ 20 in. 16 in. 8 in.] 8 in.

Q: 30 k 2 k/ft 60 k-ft 3 k/ft B 10 ft -20 ft- 10 ft

Q: Determine the normal stress in members BD, AC, and BCin the truss shown. The cross-sectional area of...

Q: The result of the liquid limit tests where N is the no of blows and w is the water content in % are ...

A: Given data in question Trial with different water content Number of blows Moisture content Plasti...

Q: Situation 2 | Beam ABCDEFG below is subjected to multiple loads as show. The total length of the bea...

A: As per bartleby guidelines, experts are allowed to solve only first three parts. If you want other...

Q: 2.00 1.00 2.00 1.00 10 KN/m 1. If the allowable axial 5 KN/m stress of steel cable is B A 140 MPa, D...

Q: For the following data, compute the horizontal distance for a recorded slope distance AB, a) AB = 38...

Q: The mass specific gravity of a soil is 1.95, while the specific gravity of soil solids is 2.7. If th...

A: Gm = 1.95 Gs = 2.7 porosity n = ?

Q: c. Explain the limitations of the Universal Soil Loss

A: NOTE:- Hi! Thank you for the question, as per the honor code, we are allowed to answer One question ...

Q: 12 KN P 14m 12KN K [4m 32 KN 6 m BA EA E 10m *- 16 m 16 m - 10 m -

Q: Can u solve this

Q: ... Вronze A = 300mm² E = 83 GPa 2.00 m Steel A = 600mm? E = 200 GPa 1.00 m A B 0.60m 1.00 m 1.00m M...

Q: In natural state, a moist soil has a volume of 0.33 ft3 and weighs 39.93 lb. The oven dry weight of ...

Q: Pb # 2: At a maximum efficiency a turbine runs at 150 rpm, discharges 10 m’/s, and develops a shaft ...

A: From Given Data; head = Reg. No/ 100 = 5262/100 =52.62m;

Q: verage hourly demand rates in gallons per minute, (a) find the uniform 24-hour pumping rate and the...

Q: Determine the normal stress in members BD, AC, and BC in the truss shown. The crosssectional area o...

A: To find normal stress in member BD,AC,BC

Q: Two members, 1 and 2, are subjected to thermal stress. Determine the compressive force acting on the...

A: Determine the compressive force acting on the members. (in kN)

Q: 2. In many cases of heavily loaded girders, shear distress is observed near the

A: To find : How much is shear distress observed.

Q: ntal cross-sectional area of 20 ft2. The roadway has a straight alignment and a badly broken and pat...

Q: Water is pumped 14.5 km from a reservoir at elevation 30 m to another reservoir at elevation 70 m. T...

Q: 2. A vertical venturi meter, 150 mm in diameter is connected to a 300 mm diameter pipe. The vertical...

Q: Question 3 An 4.3 meter aluminum square wire is hanging vertically. A tensile load of 350 KN is app...

A: As per bartleby policy i can do only one question at a time. Please upload again other questions. So...

Q: 62. In many cases of heavily loaded girders, shear distress is observed near the A. O Edges B. O Sup...

A: Answer : option (B) supports. . is correct. More explanation is given in next step

Q: Determine the reactions at support A. A=375 lb F= 500 lb B. 05 ft 8 ft 6 ft 5 t- 30 F= 160 lb

A: A loaded beam is given and it has been asked to determine the support reactions. please refer step 2...

Q: Determine the maximum compressive force developed in member BG of the side truss in Figure 1 due to...

Q: 12 KN. P 4m 12KN K M 4m F. 32 KN 6 m E A스 B, e 10m 16 m 16 m 10 m-

Q: Q12 (Simple stress and strain) Item 3 of 3 A bar AB (A = 500 mm?) is hinged at A and is supported by...

A: W=90kN E=200GPa

Q: Determine static indeterminacy of truss structure

A: This question is related to the Determinacy and Indeterminacy from Structural Analysis.

Q: The result of the liquid limit tests where N is the no of blows and w is the water content in % are ...

A: optiona (a) is the correct answer

Q: 2.00 1.00 2.00 1.00 10 KN/m F 1. If the allowable axial stress of steel cable is 5 KN/m A 140 MPa, D...

A: To find diameter of rod

Q: How I find gamma dry for layer 2?

A: Given Layer 2 of silty clay Gamma total, γb = 15 kN/m3 OCR = 1.2 Cc = 0.2 To Determine Gamma dry (Yd...

Q: A fully saturated soil sample has a volume of 28 cc. The sample was dried in oven and the weight of ...

Q: Determine the normal stress in members BD, AC, and BC in the truss shown. The cross- sectional area ...

Q: A beam has a cross section show below. If the stress at point P is 30Kpa , calculate the value for t...

A: Given values Shear stress = 30kpa Shear force, V= ? Formula used -> shear stress = V*Yc*A/INA*t W...

Q: It is an annuity where the series of uniform payment are extended forever. perpetuity annuity due de...

A: This question is related to the Estimate costing and valuation.

Q: Determine the value of longitudinal strain if poisson ratio 0.23 and lateral strain -0.25

A: Please refer the attached image for complete solution. THANK YOU !

Q: 7. A horizontal collimation test is performed on an automatic level. With the instrument setup at po...

Q: Regional Geology Lab 1-Isostasy and oceanic crust depth 1.Calculate the thickness of the lithosphere...

Q: 2.00 1.00 2.00 1.00 10 KN/m F B 5 KN/m 85° E

A: Given:- F=50kN To find:- shear stress of the pin

Q: The result of the liquid limit tests where N is the no of blows and w is the water content in % are ...

Q: 61. The repair and rehabilitation of damaged or spalled concrete is done by removing the A. O Loose ...

A: The repair and rehabilitation of damaged or spalled concrete is done by removing the loose concrete ...

Q: PROBLEM 2 A tri metallic bar is uniformly compressed by an axial force P=12kN applied through a rigi...

Q: Determine the plasticity index.

A: Soil mechanics:

Q: an original diameter of 0.5 in. and length of 9 modulus of elasticity if an axial load of 11 k 003 i...

A: Given data in question Strain Load Length Diameter To find out Elastic modulus

Q: A W10x45 column, fixed at the bottom and hinged at the top, is to compressive load of 89 kN dead loa...

A: Given, DL = 89 kN LL = 356 kN L = 10 m or 10000 mm Fy = 414 MPa

Q: . In the figure below there is an indicated stress, use the Mohr Circle and the graphical Pole Metho...

Q: The azimuths from North of lines AB and BC are 330° and 25°, respectively. If a 5°-simple curve is t...

Concept explainers

Weight-Volume relationships

Weight is defined as the quantity of matter contained in a body. Weight can also be defined as the force acting on a body due to gravity. Mathematically, weight can be defined as-

Question

a. 18.8%

b. 14.4%

c. 16.6%

d. 12.2%

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1 phase diagram

VIEW

Step 2 shrinkage limit condition

VIEW

Step 3 values at shrinkage limit

VIEW

Step 4 shrinkage limit

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 4 steps with 4 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Problem 3: In a shrinkage limit test, a sample of saturated clay was dried in the oven. The dry mass of the soil was 22.5 g. when the moisture content is at the shrinkage limit, the soil reaches a constant total volume, Vf= 10.3 cm³. calculate the shrinkage limit of the soil. (Given: G,=2.72)
A soil with a volume of 163cm^3 is sampled from a field. It weighs 221g. Then, the sample was saturated until the pores were filled and now weighs 273g. The sample was drained and weighed 236g. The sample then sat out for about 2 weeks until at equilibrium and weighed 206g. After oven drying the sample, it finally weighed 202g. If you were to fill a core with a volume of 4.5 in^3 with this same oven dry soil, how much would the soil weigh in grams?
A saturated soil is found to have a volume of 25 cc and a mass of 45 g. It is placed in an oven and dried. The dried sample is found out to have a volume of 16 cc and a mass of 31 g. 1. Determine the shrinkage limit of the soil. a. 25.16 c. 17.39 b. 35.48 d. 16.13 2. Calculate the shrinkage ratio of the soil. a. 1.79 c. 1.85 b. 1.94 d. 1.81 3. The specific gravity of the soil sample is most likely equal to: a. 2.72 c. 2.82 b. 2.78 d. 2.88
A soil with a volume of 163cm^3 is sampled from a field. It weighs 221g. Then, the sample was saturated until the pores were filled and now weighs 273g. The sample was drained and weighed 236g. The sample then sat out for about 2 weeks until at equilibrium and weighed 206g. After oven drying the sample, it finally weighed 202g. What is the percent moisture content by mass (theta g) at field capacity %?
Initial volume of soil in a saturated state = 24.6 cm³ Final volume of soil in a dry state = 15.9 cm³ Initial mass in a saturated state = 44.0 g Final mass in a dry state = 30.1 g Calculate the moisture content of the sample. Determine the shrinkage limit of the soil.
A soil sample weighs 1270g. After oven drying, volume and weight of soil reduced by 10% % and 25% respectively. The shrinkage limit of soil is
A soil with a volume of 163cm^3 is sampled from a field. It weighs 221g. Then, the sample was saturated until the pores were filled and now weighs 273g. The sample was drained and weighed 236g. The sample then sat out for about 2 weeks until at equilibrium and weighed 206g. After oven drying the sample, it finally weighed 202g. What is the percent moisture content by volume (theta v) at saturation %?
Example 2.21:The liquid limit and plastic limit of a soil are 50 % and 25 %, respectively When the soil was dried from its state at liquid limit, the decrease in volume was 40 pe cent of the volume at liquid limit. When it was dried from its state at plastic limit, the volume decrease was 20 per cent of the volume at plastic limit. Determine the shrinkag limit and shrinkage ratio.
Problem 14. The plastic limit and liquid limit of a soil are 36% and 54% respectively. The percentage volume change from the liquid limit to the dry state is 50% of the dry volume. Similarly, the percentage volume change from the plastic limit to the dry state is 29% of the dry volume. Determine the shrinkage limit. a. 9% b. 10% C. 11% d. 12%
A SOIL SAMPLE WAS TAKEN FROM A SITE AND WAS PLACED IN A CUBICAL CONTAINER WITH ONE SIDE EQUAL TO 0.1m. THE NET WEIGHT OF THE SOIL IS FOUND OUT TO BE 2kN. AFTER OVEN DRYING, THE WEIGHT WAS REDUCED TO 53%. WHAT IS THE UNIT WEIGHT OF THE SOIL AFTER DRYING? * Your answer A SATURATED SOIL HAS VOID RATIO EQUAL TO 0.65 AND sg = 2.9. WHAT IS THE SUBMERGED UNIT WEIGHT OF THE SOIL? * Your answer THE WEIGHT OF THE VOIDS OF ON SITE SOIL WAS MEASURED AND FOUND OUT TO BE 1 kN. AFTER DRYING, THE WEIGHT OF THE SOLID WAS FOUND TO BE 1 kN. IF THE VOLUME OF THE SOIL IS 0.099 m3, WHAT IS THE NATURAL UNIT WEIGHT OF THE SOIL? * Your answer
In its natural state, a moist soil has a volume of 0.009 m3 and mass of 18.9 kg . The oven dry mass of the soil is 16.13kg. If the specific gravity of the soil solids was determined in the laboratory to be 2.70, Draw the phase diagram and calculate: a. Moisture content b. Moist unit weight c. Dry unit weight d. Void ratio e. Porosity f. Degree of saturation
PROBLEM No. 5 Shrinkage Limit Following are the results of a shrinkage limit test: = 26 cm3 19 cm3 Initial volume of soil in saturated state = Final volume of soil in a dry state 46 g Initial mass in a saturated state = Final mass in a dry state = 32 g Determine the shrinkage limit of the soil Determine the shrinkage ratio Determine the specific gravity of the solids d. If the soil at natural state has a moisture content of 25%, estimate the maximum volumetric shrinkage. Estimate the linear shrinkage. а. b. С. е.