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The volume (in cubic feet) of a black cherry tree can be modeled by the equation y = -50.6+0.4x₁ +4.7x2, where x₁ is the tree's height (in feet) and x2 is the tree's diameter (in inches). Use the multiple regression equation to predict the y-values for the values of the independent variables. (a) x₁ = 73, x₂ = 8.6 (b) x₁ = 65, x₂ = 10.4 (c) x₁ = 83, x₂= 16.9 (d) x₁ = 87, x₂= 20.3

The volume (in cubic feet) of a black cherry tree can be modeled by the equation y = -50.6+0.4x₁ +4.7x2, where x₁ is the tree's height (in feet) and x2 is the tree's diameter (in inches). Use the multiple regression equation to predict the y-values for the values of the independent variables. (a) x₁ = 73, x₂ = 8.6 (b) x₁ = 65, x₂ = 10.4 (c) x₁ = 83, x₂= 16.9 (d) x₁ = 87, x₂= 20.3

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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What is the answer to part d

The volume (in cubic feet) of a black cherry tree can be modeled by the equation y = −50.6+0.4x₁ +4.7x2, where x₁ is the tree's height (in feet) and x2 is the tree's diameter (in inches). Use the multiple regression equation to predict the y-values for the values of the independent variables. (a) x₁ = 73, x₂ = 8.6 (b) x₁ = 65, x₂= 10.4 (c) x₁ = 83, x₂ = 16.9 (d) x₁ = 87, x₂ = 20.3 (a) The predicted volume is 19.0 cubic feet. (Round to one decimal place as needed.) (b) The predicted volume is 24.3 cubic feet. (Round to one decimal place as needed.) (c) The predicted volume is 62.0 cubic feet. (Round to one decimal place as needed.) (d) The predicted volume is cubic feet. (Round to one decimal place as needed.) k 20
Transcribed Image Text:The volume (in cubic feet) of a black cherry tree can be modeled by the equation y = −50.6+0.4x₁ +4.7x2, where x₁ is the tree's height (in feet) and x2 is the tree's diameter (in inches). Use the multiple regression equation to predict the y-values for the values of the independent variables. (a) x₁ = 73, x₂ = 8.6 (b) x₁ = 65, x₂= 10.4 (c) x₁ = 83, x₂ = 16.9 (d) x₁ = 87, x₂ = 20.3 (a) The predicted volume is 19.0 cubic feet. (Round to one decimal place as needed.) (b) The predicted volume is 24.3 cubic feet. (Round to one decimal place as needed.) (c) The predicted volume is 62.0 cubic feet. (Round to one decimal place as needed.) (d) The predicted volume is cubic feet. (Round to one decimal place as needed.) k 20
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