The velocity of water, v (m/s), discharged from a cylindrical tank through a long pipe can be computed as v = /2gHtanh () V2gh where g = 9.81 m/s2, H = initial head (m), L = pipe length (m), and t = elapsed time (s). Determine the head needed to achieve v = 5 m/s in 2.5 s for a 4-m-long pipe (a) graphically, (b) by bisection Employ the initial guess of x1 = 0 and Xu = 2 m with a stopping criterion of €s = 1%. Check you results.

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