The velocity distribution for the flow between two parallel plates 0.3 m apart is parabolic and the maximum velocity at the centre is 0.5 m/s. The rate of flow per unit length is:

Water flows through a pipe AB withm diameter andm/s then passes through pipe BC with diameter. The flow in branch CE is AB (in cubic meter/second), the velocity (in meter/ second) in BC and CD and the diameter (in meter) of CE if CD is m/s. Find the volume rate in m in diameter and carries 1/3 of the flow in AB. 0.8 m B. 1.2 m 1.5 m VAB- 3 m/sec Q2 E VoE 2.5 m/sec

1. The performance data of a water pump follow the curve fit Havailable =Ho +aV, where the pump's shutoff head Ho="K", coefficient a="Y" m/(Lpm)?, the units of pump head H are meters, and the units of Vare liters per minute (Lpm). The pump is used to pump water from one large reservoir to another large reservoir at a higher elevation. The free surfaces of both reservoirs are exposed to atmospheric pressure. The system curve simplifies to Hrequired =(Z2-Z1)+bV², where elevation difference z2-z1="X" m, and coefficient b = "L" m(Lpm)?. Calculate the operating point of the pump (a) V. operating and (b) Hoperating) in appropriate units (Lpm and meters, respectively). Read the equation carefully. (Zz-Z:) Но b a Y K L 0.0479 4.9 0.029

Water is flowing in a rectangular channel with a base of 4.0 ft. The velocity gradient from the bottom of the channel to the water surface is given by the equation: v=3.5y^0.6 Where y is the distance from the bottom of the channel. The total depth of the flow in the channel is 3.0ft. a) Graph the velocity profile from the bottom of the channel to the water surface.  B) Calculate the flow rate by integration. The first step is to draw a cross-section of channel and on that cross-section, Draw on your figure an elemental area DA that you will then ise in the equation: Q=integral V.dA