Question
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by stepSolved in 2 steps with 2 images
Knowledge Booster
Similar questions
- Pls help on this question.arrow_forwardWhat is the raot-mean- Square Speed in mis of molecules with molar molecular weight 33 giměl at a temperature of 87.29 °C? gasarrow_forwardIf you double the typical speed of the molecules in a gas, by what factor does the pressure change? Give a simple explanation why the pressure changes by this factor.arrow_forward
- The following figure is a histogram showing the speeds of the molecules in a very small gas. What are (a) the most probable speed, (b) the average speed, and (c) the rms speed?arrow_forwardASAParrow_forwardThe rms average speed of a nitrogen molecule at 20 K is 133.427875 m/s. What is the rms average speed at 80 K?arrow_forward
- What is the root mean squared velocity of Nitrogen gas at room temperature (295 K)? The mass of N2 is 4.65 x 10-26 kg. Is every gas molecule moving at this speed?arrow_forwardA glass container encloses a low pressure of 02 gas at 298 K. The molecular weight of 02 is 32.0 g/mol. (A) Calculate the mean squared velocity, v², of these molecules in units of m²/s². (B) Find the root mean squared speed along the x-axis, Vx. (C) Would Vx be lower, higher, or the same under the same conditions if the gas were He instead of 02? Please explain your answer in 15 words or less.arrow_forwardShow that the rms speed of molecules in a gas is given by ЗР Vrms where P is the pressure in the gas, and p is the gas density.arrow_forward
- A room is 10.0 m by 7.5 m by 2.7 m is filled with air at 22oC and 1 atm. The average molar mass of air is 28.8 g/mol. Find the number of moles of air to fill the room and the weight of the air in kg.arrow_forwardThe root mean square velocity of an oxygen molecule is 1,302.27 m/s. Estimate the temperature at which it is located.arrow_forwardFind the total number of collisions between molecules in 1.00 s in 1.00 L of nitrogen gas at standard temperature and pressure ( 0 °C , 1.00 atm). Use 1.88 × 10−10 m as the effective radius of a nitrogen molecule. (The number ofcollisions per second is the reciprocal of the collision time.) Keep in mind that each collision involves two molecules, so if one molecule collides once in a certain period of time, the collision of the molecule it hit cannot be counted.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios