The vapor pressure of diethyl ether (ether) is 463.57 mm Hg at 25 °C. A nonvolatile, nonelectrolyte that dissolves in diethyl ether is aspirin. Calculate the vapor pressure of the solution at 25 °C when 10.17 grams of aspirin, C9H8O4 (180.1 g/mol), are dissolved in 151.7 grams of diethyl ether. diethyl ether = CH3CH2OCH2CH3 = 74.12 g/mol. The vapor pressure of diethyl ether (ether) is 463.57 mm Hg at 25°C. How many grams of estrogen (estradiol), C18H24O2, a nonvolatile, nonelectrolyte (MW = 272.4 g/mol), must be added to 192.1 grams of diethyl ether to reduce the vapor pressure to 452.63 mm Hg ? diethyl ether = CH3CH2OCH2CH3 = 74.12 g/mol.
The vapor pressure of diethyl ether (ether) is 463.57 mm Hg at 25 °C. A nonvolatile, nonelectrolyte that dissolves in diethyl ether is aspirin.
Calculate the vapor pressure of the solution at 25 °C when 10.17 grams of aspirin, C9H8O4 (180.1 g/mol), are dissolved in 151.7 grams of diethyl ether.
diethyl ether = CH3CH2OCH2CH3 = 74.12 g/mol.
The vapor pressure of diethyl ether (ether) is 463.57 mm Hg at 25°C.
How many grams of estrogen (estradiol), C18H24O2, a nonvolatile, nonelectrolyte (MW = 272.4 g/mol), must be added to 192.1 grams of diethyl ether to reduce the vapor pressure to 452.63 mm Hg ?
diethyl ether = CH3CH2OCH2CH3 = 74.12 g/mol.
#Q.1:
Given the vapor pressure of pure diethyl ether, Po = 463.57 mm Hg
Moles of aspirin added = mass / molar mass of aspirin = 10.17 g * (1 mol / 180.1 g)
=> Moles of aspirin added = 0.05646863 mol
Moles of diethyl ether added = mass / molar mass of diethyl ether = 151.7 g * (1 mol / 74.12 g)
=> Moles of diethyl ether added = 2.046681 mol
Step by step
Solved in 4 steps