The values of K a for hydrozoic acid ( HN 3) and hypobromous acid (HBrO) are given below. HN3 Ka = 1.9 x 10°s HBRO Ka = 2.0 x 10-9 If we mix 0.50 mol HN 3 and 0.50 mol NaBrO into a 1-L aqueous solution, which of the following statements is correct concerning the final solution at equilibrium after mixing? O a. The pH of the final solution is greater than 7 because K, (HN3) < K½( BrO" ). O b. The pH of the final solution is greater than 7 because K, (HN3) > K½(BrO"). O. The pH of the final solution is equal to 7 because the neutralization reaction between HN3 and NaBrO. O d. The pH of the final solution is less than 7 because K. (HN2) > KL( BrO" ).

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The values of K a for hydrozoic acid ( HN 3) and hypobromous acid (HB1O) are given below.
HN3
Ką = 1.9 x 10-5
HBrO
Ka = 2.0 x 10-9
If we mix 0.50 mol HN 3 and 0.50 mol NaBrO into a 1-L aqueous solution, which of the following statements is
correct concerning the final solution at cquilibrium after mixing?
O a. The pH of the final solution is greater than 7 because Ką (HN3) < Kp( BrO" ).
Ob. The pH of the final solution is greater than 7 because Ką (HN3) > K½(BrO").
O . The pH of the final solution is equal to 7 because the neutralization reaction between HN3 and NaBro.
d. The pH of the final solution is less than 7 because Ką (HN3) > Kh( BrO" ).
O e. The pH of the final solution is less than 7 because Ką (HN3) < K,( BrO" ).
Transcribed Image Text:The values of K a for hydrozoic acid ( HN 3) and hypobromous acid (HB1O) are given below. HN3 Ką = 1.9 x 10-5 HBrO Ka = 2.0 x 10-9 If we mix 0.50 mol HN 3 and 0.50 mol NaBrO into a 1-L aqueous solution, which of the following statements is correct concerning the final solution at cquilibrium after mixing? O a. The pH of the final solution is greater than 7 because Ką (HN3) < Kp( BrO" ). Ob. The pH of the final solution is greater than 7 because Ką (HN3) > K½(BrO"). O . The pH of the final solution is equal to 7 because the neutralization reaction between HN3 and NaBro. d. The pH of the final solution is less than 7 because Ką (HN3) > Kh( BrO" ). O e. The pH of the final solution is less than 7 because Ką (HN3) < K,( BrO" ).
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