The UCLA biomedical lab is running a Chi-Squared analysis and have set their significance at 95%. Based on the following statistical statement, χ2(1, N = 72) = 8.85, p < .001, the researchers should fail to reject the null?

The manufacturer claims that your new car gets 24 mpg on the highway. You suspect that the mpg is less for your car. The 44 trips on the highway that you took averaged 22.3 mpg and the standard deviation for these 44 trips was 4.2 mpg. What can be concluded at the  αα = 0.05 level of significance? For this study, we should use (t-test for population mean, z-test for population proportion)    The null and alternative hypotheses would be:       H0: (symbol) (symbol) ____                H1:  (symbol) (symbol) ____             The test statistic (?,t,z)    =  (please show your answer to 3 decimal places.) The p-value =  (Please show your answer to 4 decimal places.) The p-value is (?, less than or equal to, more than)  αα Based on this, we should (accept, reject, fail to reject) the null hypothesis. Thus, the final conclusion is that ... The data suggest that the sample mean is not significantly less than 24 at αα = 0.05, so there is statistically insignificant evidence to conclude…

Suppose you had obtained a test statistic of 2.45 (this is incorrect). What would the P-value be? Draw a conclusion based on a = 0.01. Select one: O a. 0.01 < P-value < 0.02, we fail to reject Ho and do not have sufficient evidence to conclude that the mean difference in LDL from switching from an omnivorous to a plant-based diet for 6 weeks is not the same for men and women. O b. 0.005 < P-value < 0.01, we fail to reject Ho and do not have sufficient evidence to conclude that the mean difference in LDL from switching from an omnivorous to a plant-based diet for 6 weeks is not the same for men and women. O c. 0.01 < P-value < 0.02, we reject Ho and have sufficient evidence to conclude that the mean difference in LDL from switching from an omnivorous to a plant-based diet for 6 weeks is not the same for men and women. O d. 0.005 < P-value < 0.02, we reject Ho and have sufficient evidence to conclude that the mean difference in LDL from switching from an omnivorous to a plant-based diet…

You are conducting a study to see if the proportion of women over 40 who regularly have mammograms is significantly less than 0.24. Thus you are performing a left-tailed test. Your sample data produce the test statistic z=−2.665z=-2.665. Find the p-value accurate to 4 decimal places.