The two variables a and b have initial values of 1 and 2, respectively. The following code is for a Linux system: Thread 1 a = 3; mb (); b=4; - - Thread 2 c = b; rmb(); d = a; What possible errors are avoided by the use of the memory barriers?
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- My task from the teacher is to create a program that solves the three problems using threads in Python: 2 files: reader.py and writer.py In the readers-writers problem there is a common resource where a group of actors called readers want to read from the resource and another group of actors called writers want to write to the resource. The basic synchronization problem that needs to be solved is:1. Mutual exclusion of the resource, where:• only one writer may print at a time, and• no writer may write while a reader is reading.An ordinary mutex lock that is applied equally to all actors can solve this but will lead to only one actor being able to enter its critical section at a time. This is a problem as we normally want several readers to be able to read at the same time. The next problem that needs to be solved is therefore the following: 2. Several readers should be able to read the resource at the same time.In a solution where several readers can read simultaneously and lock out…Linux supports all available concurrent techniques. A lot of people don't.<<Java Programming>> Question: Your job is to write a java program where 3 people (X, Y, Z) will communicate with each other. It's a conversation between these 3 people! You have to use multi-threading and they will continue their conversation till 1 person/1 Thread says "BYE"! When 1 person says bye it will print "X/Y/Z is no longer available in this chat" [I'm a beginner it will be great if you add more and more comments!! Please use basic java methods, not pro-level! It will be more than great if you add a flow chart of your process]
- Hello Can you please help me with this code because I am struggling how do to this, can you please help me this code has to be in C. Write a multithreaded program that calculates various statistical values for a list of numbers. This program will be passed a series of numbers on the command line and will then create three separate worker threads. One thread will determine the average of the numbers, the second will determine the maximum value, and the third will determine the minimum value. For example, suppose your program is passed the integers 90 81 78 95 79 72 85 The program will report The average value is 82 The minimum value is 72 The maximum value is 95 The variables representing the average, minimum, and maximum values will be stored globally. The worker threads will set these values, and the parent thread will output the values once the workers have exited. (We could obviously expand this program by creating additional threads that determine other statistical values, such as…The two variables a and b have initial values of 1 and 2, respectively. The following code is for a Linux system: Thread 1 a = 3; mb (); b=4; - Thread 2 c = b; rmb(); d = a; What possible errors are avoided by the use of the memory barriers?You'll write a C++ program to demonstrate thread synchronization. Your main function should first create an empty file called *sync.txt*. Then it will create two separate threads: *Thread-A* and *Thread-B*. Both threads will open *sync.txt* and write to it simultaneously. *Thread-A* will write the numbers 0 through 9, a total of fifty-thousand times in nested `for` loops, then exit. In other words, print the numbers 0 through 9 over and over again, with each run on a separate line, for 50,000 lines. Here's an example of one such line: ```text 0 1 2 3 4 5 6 7 8 9 ``` Somewhat similarly, *Thread-B* will write the letters A through Z fifty-thousand times in nested `for` loops, then exit. In other words, print the letters A through Z over and over again, with each run on a separate line, for 50,000 lines. Here's an example of one such line: ```text A B C D E F G H I J K L M N O P Q R S T U V W X Y Z ``` Do not write each line as one long string. You must write each character to the…
- Write a C program called threadcircuit to run on ocelot which will provide a multithreaded solution to the circuit-satisfiability problem which will compute for what combinations of input values will the circuit output the value 1. This is the sequential solution, which is also attached. You should create 8 threads and divide the 65,536 test cases among them. For example, if p=8, each thread would be responsible for roughly 65,536/8 number of iterations (if it's not divisible, some threads can end up with one more iteration than the others). #include <stdio.h>#include <sys/time.h> /* Return 1 if 'i'th bit of 'n' is 1; 0 otherwise */#define EXTRACT_BIT(n,i) ((n&(1<<i))?1:0) int check_circuit (int z) {int v[16]; /* Each element is a bit of z */int i; for (i = 0; i < 16; i++) v[i] = EXTRACT_BIT(z,i);if ((v[0] || v[1]) && (!v[1] || !v[3]) && (v[2] || v[3])&& (!v[3] || !v[4]) && (v[4] || !v[5])&& (v[5] || !v[6]) &&…Question p How large (in bytes) is this structure on a x86-64 Linux system?.Full explain this question and text typing work only We should answer our question within 2 hours takes more time then we will reduce Rating Dont ignore thisUsing the synchronization mechanism of C++, write a program that prints on the screen the integers from 10 to 150 divisible at 3, 5, 7, 11. The printing task is divided into four threads 1. Thread #1 prints the number divisible by 3. 2. Thread #2 prints the number divisible to 5. 3. Thread #3 prints the number divisible to 7. 4. Thread #4 prints the number divisible to 11.
- Please give me correct solution.Computer Science #include<cmath>#include<stdio.h>__global__voidprocess_kernel1(float *input1,float *input2,float *output,int datasize){int idx = threadIdx.x + blockIdx.x * blockDim.x;int idy = threadIdx.y + blockIdx.y * blockDim.y;int idz = threadIdx.z + blockIdx.z * blockDim.z;int index = idz * (gridDim.x * blockDim.x) * (gridDim.y*blockDim.y) + idy * (gridDim.x * blockDim.x) +idx;if(index<datasize)output[index] = sinf(input1[index]) + cosf(input2[index]);}__global__voidprocess_kernel2(float *input,float *output,int datasize){int idx = threadIdx.x + blockIdx.x * blockDim.x;int idy = threadIdx.y + blockIdx.y * blockDim.y;int idz = threadIdx.z + blockIdx.z * blockDim.z;int index = idz * (gridDim.x * blockDim.x) * (gridDim.y*blockDim.y) + idy * (gridDim.x * blockDim.x) +idx;if(index<datasize)output[index] = logf(input[index]);}_global__voidprocess_kernel3(float *input,float *output,int datasize){int idx = threadIdx.x + blockIdx.x *…The two variables a and b have initial values of 1 and 2, respectively. The following code is for a Linux system: Thread 1 a = 3; mb (); b=4; - Thread 2 c = b; rmb(); d = a; What possible errors are avoided by the use of the memory barriers?