The two parallel plates in the figure (Figure 1)are 2.0 cm apart and the electric field strength between them is 1.30 x10 N/C. An electron is launched at a 45° angle from the positive plate. Part A What is the maximum initial speed vo the electron can have without hitting the negative plate? Express your answer with the appropriate units. • View Available Hint(s) HA Value Units Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Figure < 1 of 1 Provide Feedback 2.0 cm 45° 十十十十十+十十

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Part A An electric dipole is formed from two charges, +q, spaced 0.600 cm apart. The dipole is at the origin, oriented along the y-axis. The electric field strength at the point (r, y) = (0 cm, 10 cm) is 340 N/C What is the charge q? Give your answer in nC. Express your answer in nanocoulombs to three significant figures. > View Available Hint(s) ΑΣφ q =160 nC Submit Previous Answers Incorrect; Try Again; 3 attempts remaining Part B What is the electric field strength at the point (x, y) = (10 cm, 0 cm)? Express your answer with the appropriate units. View Available Hint(s) HA E= Value Units Submit

A point charge with charge q1 = 2.30 μC is held stationary at the origin. A second point charge with charge q2 = -4.90 μC moves from the point (0.140 m, 0) to the point (0.260 m, 0.235 m ). Part A How much work is done by the electrostatic force on the moving point charge? Express your answer in joules. ►View Available Hint(s) W = 跖 ΤΟ ΑΣΦ ? J

Part A An electron moving parallel to a uniform electric field increases its speed from 2.0x10' m/s to 4.0×10 m/s over a distance of 1.2 cm. What is the electric field strength? Express your answer with the appropriate units. HA E = Value Units Submit Request Answer

Electric Fields 1. A wire has been given a net positive electric charge Q evenly distributed along its length. The wire has a length of L and is located on the x-axis with its left end at the origin as drawn. Set up the integral you need to do to find the electric field at a distance d to the left of the origin. Some steps you may wish to follow are: a. Figure out the direction the electric field will have at our location x = -d. This will be the same as f b. Write the differential charge dą in terms of the charge per length and a differential length. c. ris a function of x which means we have to integrate to find the electric field. Write down r. d. Put everything together (including the vector direction) into one integral that would allow you to find the E-field. Write this in the box below. e. You are not required to complete the integral and no credit is given for completing the integral. d dE =

A proton enters the uniform electric field produced by the two charged square plates shown below. The plates carry charges +Q and -Q, where the magnitude Q=1 μC. The speed of the proton when it enters the region between the plates is 2 x 107 m/s. 12.0 cm- #3 3 Figure Description Hint a. What is the magnitude of electric field in the region? Assume that the plates are close enough together to be treated as "infinite" planes for electric field between them. N/C. Enter an integer or decimal number [more..] b. What distance d has the proton been deflected downward when it leaves the region between the two plates? Assume that the electrostatic force is the only force on the charge. d= E= Submit Question $ 4 cm. % 5 MacBook Pro <6 A 6 Hey & 7 We 8

3. A positive charge of magnitude q, is shown at the right. Points B and C are a distance ro from the charge and point A is a distance 2r. from it. Let WAB represent the work done by an external agent in moving a small test charge from point A to point B. a. Use an arrow to indicate the direction of the electric field at points A, B, and C. X A X B X C qo b. Would the absolute value of the work done by an external agent in moving the same test charge from point B to point C be greater than, less than, or equal to WAB? Explain. c. Would the absolute value of the work done by an external agent in moving the same test charge from point A to point C be greater than, less than, or equal to WAB? Explain.