The two cylindrical rod segments shown in the figure below (Figure 1) are fixed to the rigid walls such that there is a gap of 0.01 in . between them when T = 60°F . Each rod has a diameter of 1.9 in Take aal = 13(10 6)/°F, Ea = 10(10³) ksi . (oY)al = 40 ksi , Acu = 9.4(10 5)/°F . (OY)cu= 50 ksi , and Ecu = 15(10*) ksi . %3| Figure < 1 of 1 > 0.01 in - Соррer Aluminum -12 in.- - 6 in.-

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
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T2=400°F

Part B
Calculate the new length of the aluminum segment.
Express your answer to six significant figures and include appropriate units.
?
La = 6.00312
ksi
Transcribed Image Text:Part B Calculate the new length of the aluminum segment. Express your answer to six significant figures and include appropriate units. ? La = 6.00312 ksi
The two cylindrical rod segments shown in the figure below (Figure 1)
are fixed to the rigid walls such that there is a gap of 0.01 in . between
them when T = 60°F . Each rod has a diameter of 1.9 in Take
aal = 13(10 6)/°F, Ea = 10(10³) ksi . (oY)al = 40 ksi ,
Acu = 9.4(10 5)/°F . (OY)cu= 50 ksi , and Ecu = 15(10*) ksi .
%3|
Figure
< 1 of 1 >
0.01 in -
Соррer
Aluminum
-12 in.-
- 6 in.-
Transcribed Image Text:The two cylindrical rod segments shown in the figure below (Figure 1) are fixed to the rigid walls such that there is a gap of 0.01 in . between them when T = 60°F . Each rod has a diameter of 1.9 in Take aal = 13(10 6)/°F, Ea = 10(10³) ksi . (oY)al = 40 ksi , Acu = 9.4(10 5)/°F . (OY)cu= 50 ksi , and Ecu = 15(10*) ksi . %3| Figure < 1 of 1 > 0.01 in - Соррer Aluminum -12 in.- - 6 in.-
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