The "Triple-Alpha Process" is a nuclear fusion process that fuses three "He intoone 12C, 3 4He → 12C+ energy. (The 4He nucleus is called an "alpha particle,"which is related to alpha radiation.) If the nuclei are all in their ground states,and have negligible kinetic energy, how much energy is released in this reaction?Ofcourse,this is not how quantum mechanics works. It's much more likely forthis process to occur if the total energy of three "He particles is equal to one ofthe allowed energy states of 12C. It turns out that there is an excited state ofthe 12C nucleus, call it 12C*, that is 7.656 MeV above the ground state nucleus.Calculate the mass of 12C* and its binding energy.

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The "Triple-Alpha Process" is a nuclear fusion process that fuses three "He into one 1²C, 3 4He → 1²C+ energy. (The 4He nucleus is called an “alpha particle," which is related to alpha radiation.) If the nuclei are all in their ground states, and have negligible kinetic energy, how much energy is released in this reaction? Of course, this process to occur if the total energy of three "He particles is equal to one of the allowed energy states of 12C. It turns out that there is an excited state of the 12C nucleus, call it 12C*, that is 7.656 MeV above the ground state nucleus. Calculate the mass of 12C* and its binding energy. this is not how quantum mechanics works. It's much more likely for

The "Triple-Alpha Process" is a nuclear fusion process that fuses three "He into one 1²C, 3 4He → 1²C+ energy. (The 4He nucleus is called an “alpha particle," which is related to alpha radiation.) If the nuclei are all in their ground states, and have negligible kinetic energy, how much energy is released in this reaction? Of course, this process to occur if the total energy of three "He particles is equal to one of the allowed energy states of 12C. It turns out that there is an excited state of the 12C nucleus, call it 12C, that is 7.656 MeV above the ground state nucleus. Calculate the mass of 12C and its binding energy. this is not how quantum mechanics works. It's much more likely for

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Concept explainers

Nuclear Fission

Nuclear fission is a type of nuclear reaction in which heavier nuclei split into lighter nuclei by releasing a large quantity of energy. The elements like uranium-235 and plutonium-239 isotope undergo nuclear fission releasing energy. When nuclei undergo fission, some quantity of mass is lost. The lost mass is converted to nuclear energy. Nuclear fission reaction is used in nuclear power plants and atomic bombs. In nuclear power plants, nuclear reactors are used to generate electricity.

Endothermic Nuclear Reaction

A nuclear reaction can be described as a process where two atoms, or two nuclei or nucleus and subatomic particles such as a proton, neutron interact together, and a large amount of energy is produced and new elements are also produced.

Question

The "Triple-Alpha Process" is a nuclear fusion process that fuses three "He into
one 12C, 3 4He → 12C+ energy. (The 4He nucleus is called an "alpha particle,"
which is related to alpha radiation.) If the nuclei are all in their ground states,
and have negligible kinetic energy, how much energy is released in this reaction?
Of
course,
this is not how quantum mechanics works. It's much more likely for
this process to occur if the total energy of three "He particles is equal to one of
the allowed energy states of 12C. It turns out that there is an excited state of
the 12C nucleus, call it 12C*, that is 7.656 MeV above the ground state nucleus.
Calculate the mass of 12C* and its binding energy.

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