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A five-sided closed field traverse has the following distances in meters: AB = 51.766; BC = 26.947; CD =37.070; DE = 35.292; EA = 19.192. The adjusted angles are as follows: A = 101°03′19″; B = 101°41′49″; C =102°22′03″; D = 115°57′20″; E = 118°55′29″. The bearing of AB is N 75°05′30″ E. BC is in the S.E. quadrant OR BC runs in the direction of South East. What do the interior angles add up to be and do they meet the interior angle check (n-2)*180?
What is the Azimuth of BC?
What is the Azimuth of CD?
What is the Azimuth of DE?
What is the Azimuth of EA?
What is the the Latitude of BC?
What is the the Latitude of DE
What is the the Departure of AB?
What is the the Departure of CD?
What is the the Departure of EA?
What is the the total perimeter distance of the traverse?
What is the the total error in the Latitudes? (OR what is the total when you add up all of the latitudes?)
What is the the total error in the Departures? (OR what is the total when you add up all of the Departures?)
What is the total error or actual error or [sqrt of (Lats²+Deps²)]?
What is the acceptable error or Perimeter/10000? Does the Actual error meet the acceptable standards or not?
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- Compute the area of the given traverse using DPD and DMD method. COURSE LENGTH (m) BEARING АВ 495.85 N 05° 30' E ВС 850.62 N 46° 02' E CD 855.45 S 67° 38 E DE 1020.87 S 12° 25 E EF 1117.26 S 83° 44' W FA 660.08 N 55° 09' Warrow_forwardConsider a five-sided closed polygon traverse. The azimuth of side AB is fixed at 218°59′30". A = 132°47′06", B = 108°46'18", C = 107°19′37", D = 81°50′36", E = 109°16′18". (Note: line BC bears SE.) The lengths of the sides (in feet) are as follows: AB = 202.74, BC = 283.87, CD = 498.37, DE = 320.33, and EA = 380.78. The coordinates of station A are X = 20, 000.00 ft and Y = 15,000.00 ft. ▼ Part A Use the coordinate method to compute the area enclosed by the traverse above. Express your answer to two significant figures and include appropriate units. Note: Traverse does not need to be adjusted to determine the correct answer.arrow_forwardQ.2. A five-sided closed field traverse has the following angles: A= (101°03'39"); B=(101°42'09"); C=(102°22'23"); D=(115°57'40"); E=(118°55'49"). The lengths of the sides are as follows: AB = 51.766m; BC=26.947m; CD=37.070m; DE =35.292m; EA = 19.192m. The Azimuth of AB is (75°05'30"). BC is in the S. E. quadrant. Figure is not scaled. B 26.947 m 101° 42' 09" 51.766 m 102° 22' 23" 101° 03' 39" A 19.192 m 118° 55' 49" E 115° 57' 40" 35.292 m a) Compute the bearing of CD and azimuth of DE. b) Determine the linear error of closure (E) and the precision ratio. c) Determine the balanced latitude of BC, the balanced latitude of CD and the balanced departure of DE using the compass rule. 37.070 marrow_forward
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