The transmission tower is subjected to the forces F₁ = 3.6 KN at = 50° and F2 = 3.3 kN at 6 = 35°. Determine the forces in members BC, BP, PQ, PC, CD, DP and NP. Use positive values to indicate tension and negative values to indicate compression. кажажь жажах ↑ d d h K L N M IF, P B Q CENTER LINE R Cc ④ BY NC SA kbb 2013 Michael Swanbom Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value 1.7 m a b 4.9 m C 3 m d 5.2 m h 8.4 m Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable a Value 1.7 m b 4.9 m 3 m с d 5.2 m h 8.4 m The force in member BC is The force in member BP is The force in member PQ is The force in member PC is The force in member CD is The force in member DP is The force in member NP is KN. KN. KN. KN. KN. KN. KN. į į į į Ź Ź Ź

200 N A block placed under the head, of the claw hammer as shown greatly facilitates the extraction of the nail. If the 200-N pull on the handle is required, to pull the nail calculate the tension T in the nail and the magnitude A of the force exerted by the hammer head on the block. The contacting surfaces at A are sufficiently rough to 200 mm 20 45 mm prevent slipping 1. 50- |Imm L->

The transmission tower is subjected to the forces F = 8 kN at 0 = 54° and F2 = 5.7 kN at o = 31°. Determine the forces in members BC, BP, and PQ. Use positive values to indicate tension and negative values to indicate compression. ka*a b *a>*a H. K G D N d P F2 d B. Q h A, R cc BY NC SA kb * b> -6 2013 Michael Swanbom Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value 1.3 m 4.1 m 2.3 m 5.2 m 8.3 m h The force in member BC is kN. The force in member BP is kN. The force in member PQ is kN. CENTER LINE

Answer should be Mf = 192..5 lbs and T=15.8lb

Need help, round answers to 3 sig figs please

Q) Determine the tension in cables BA and BC necessary to support the 60 kg cylinder as shown in figure helow. , TBC Solution: Tecsin45 TRAsing 45 X. Ta:cos0 Taccos45 W = mg 53 W =mg = 60*9.81 = 588.6 N 0 = tan (3:4) = 37 Σ-0 Tục cos45 – TBAcos37 0 (1) EF, = 0 TBCsin45 + TBASin37- w 0

3_8

6

A statically determinate truss is one of the early problems addressed in sophomore statics classes. A typical problem is shown in figure below: 2 Fapplied √30° F₁ F3 F2 02 3 L. Hinge Roller The applied force has a magnitude of 1000 N at an angle of 30° from the horizontal, as shown in the figure. The inner angles ₁ and 2 are 45° and 65° respectively. Determine the values of the forces in each member of the truss, and the reactive forces experienced at the hinge and the roller (nodes 2 and 3). Set up the problem using a simultaneous equation system. Use the method of the inverse matrix taught in the lectures. Follow the steps a) to e) as indicated below (assume "S" as the matrix representing the previous system. a) Calculate the matrix of minors of S. b) Calculate the matrix of cofactors of S (name it H) c) Calculate the determinant of S. d) Calculate the Adjoint of matrix of S using adj S = HT e) Calculate the inverse of matrix S using S₁ = adj S/|S|

no matter what calculaton I make I keep getting numbers that aren't even close to what they should be, can you help me figure out what I am missing with this?