MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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- Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 4.7 parts/million (ppm). A researcher believes that the current ozone level is not at the normal level. The mean of 13 samples is 4.9 ppm with a standard deviation of 1.0. Does the data support the claim at the 0.1 level? Assume the population distribution is approximately normal. Step 3 of 3: Make the decision to reject or fail to reject the null hypothesis.arrow_forwardThe systolic blood pressure (given in millimeters) of males has an approximately normal distribution with mean u = 125 and standard deviation o = 12. (a) Calculate the z-scores for the male systolic blood pressures 110 and 140 millimeters. (Round your answers to two decimal places.) 110 mm z = 140 mm z = (b) If a male friend of yours said he thought his systolic blood pressure was 2.5 standard deviations below the mean, but that he believed his blood pressure was between 110 and 140 millimeters, what would you say to him? (Enter your numerical answer to the nearest whole number.) He is ---Select--- because 2.5 standard deviations below the mean would give him a blood pressure reading of millimeters, which is ---Select--- the range of 110 to 140 millimeters.arrow_forwardIt takes an average of 9.1 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will increase if the patient is immediately told the truth about the injury. The EMT randomly selected 45 injured patients to immediately tell the truth about the injury and noticed that they averaged 9.1 minutes for their blood to begin clotting after their injury. Their standard deviation was 0.91 minutes. What can be concluded at the the αα = 0.10 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer > < ≠ = H1:H1: ? μ p Select an answer = < ≠ > The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer accept fail to reject reject…arrow_forward
- In a sample of 14 randomly selected high school seniors, the mean score on a standardized test was 1184 and the standard deviation was 162.8. Further research suggests that the population mean score on this test for high school seniors is 1014. Does the t-value for the original sample fall between - to 99 and to 99? Assume that the population of test scores for high school seniors is normally distributed. The t-value of t = fall between to.99 and to.99 because to.99 %3D (Round to two decimal places as needed.)arrow_forwardA survey collected data from a random sample of 121 people living in Jade city. The sample average of the distance people travel to reach their workplaces (Y) is 23.28 km and the standard deviation (sy) is 7.48 km. The standard error of the sample average of the distance people travel to reach their workplaces is 68 km. (Round your answer to two decimal places.) Let μy denote the mean of the distance all the people in Jade city travel to reach their workplaces. The p-value of the test Ho: #y #22 km vs. H₁: Hy #22 km is (Round your answer to two decimal places.)arrow_forwardIt takes an average of 14.5 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will increase if the patient is immediately told the truth about the injury. The EMT randomly selected 65 injured patients to immediately tell the truth about the injury and noticed that they averaged 15.4 minutes for their blood to begin clotting after their injury. Their standard deviation was 3.05 minutes. What can be concluded at the the αα = 0.05 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: H1:H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton mean is significantly greater than 14.5 at αα = 0.05, so there is statistically significant…arrow_forward
- It takes an average of 10.8 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will increase if the patient is immediately told the truth about the injury. The EMT randomly selected 46 injured patients to immediately tell the truth about the injury and noticed that they averaged 11.7 minutes for their blood to begin clotting after their injury. Their standard deviation was 2.98 minutes. What can be concluded at the the αα = 0.05 level of significance? The null and alternative hypotheses would be: Please provide number H0:H0: mean =Correct __?__ H1:H1: mean > Correct_ __?__ The test statistic t = __?__ (please show your answer to 3 decimal places.) The p-value = __?__ (Please show your answer to 4 decimal places.)arrow_forwardThe level of calcium in the blood of healthy young adults follows a normal distribution with mean u = 10 milligrams per deciliter and standard deviation s = 0.4. A clinic measures the blood calcium of 100 healthy pregnant young women at their first visit for prenatal care. The sample mean of these 100 measurements is X = 9.8. Is this evidence that the mean calcium level in the population from which these women come is less than 10? To answer this question, we perform the following hypothesis test: H0: u = 10, Ha: u < 10. What is the test statistic? (use two decimal places in your answer) What is the p-value equal to? At the 10% significance level, do you accept or reject the null hypothesis? Answer ACCEPT or REJECT t the 5% significance level, do you accept or reject the null hypothesis? Answer ACCEPT or REJECTarrow_forwardA standardized test is given to a sixth-grade class. Historically the mean score has been 151 with a standard deviation of 21. The superintendent believes that the standard deviation of performance may have recently decreased. She randomly sampled 23 students and found a mean of 161 with a standard deviation of 18.2898. Is there evidence that the standard deviation has decreased at the α=0.05 level? Step 1 of 5 : State of the hypotheses in terms of the standard deviation. Round the standard deviation to four decimal places when necessary Step 2 of 5 : Determine the critical value(s) of the test statistic. If the test is two-tailed, separate the values with a comma. Round your answer to three decimal places. Step 3 of 5 : Determine the value of the test statistic. Round your answer to three decimal places. Step 4 of 5 : Make the decision. Step 5 of 5 : What is the conclusion?arrow_forward
- Although, it is commonly believed that the mean for the human body temperature is 98.6 F, others doubt it. A random sample of 100 persons showed the mean body temperature to be 98.4 F with standard deviation of .76 F. At a .05 level of significance, find if the data indicates that the mean for the human body temperature is not equal to 98.6. Find t*arrow_forwardIt takes an average of 12.7 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will decline if the patient is immediately told the truth about the injury. The EMT randomly selected 51 injured patients to immediately tell the truth about the injury and noticed that they averaged 12.4 minutes for their blood to begin clotting after their injury. Their standard deviation was 3.77 minutes. What can be concluded at the the αα = 0.10 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? p μ Select an answer > < ≠ = H1:H1: ? p μ Select an answer = < ≠ > The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject accept fail to reject…arrow_forwardOur environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 5.8 parts/million (ppm). A researcher believes that the current ozone level is at an excess level. The mean of 26 samples is 5.9 ppm with a standard deviation of 0.6. Does the data support the claim at the 0.01 level? Assume the population distribution is approximately normal. Step 1 of 5: State the null and alternative hypotheses. Answer Ho: Ha: Tables Keypad Keyboard Shortcutsarrow_forward
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