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- A 22-k resistor and a 0.02-F capacitor are connected in series to a 5-V source. How long will it take the capacitor to charge to 3.4 V Select one: a. 0.501 ms b. 0.66 ms c. 0.44 ms d. 0.70 msAn inductor of 230 milli Henry, a capacitor of 15 micro farad and a 200 ohm resistor are in series across a 36 V and 60 Hz voltage source. Find the total current a. 150 mA b. 0.164 A c. 0.2 A d. 170 mAHere are the values of the resistors, capacitance and the Is. Is= 7.8 A , r1= 7.1 ohms , r2= 3.8 ohms , r3= 5.5 ohms , C= 1 uF
- (c) The capacitors are connected as shown in Figure 3 and charged by a 100 V battery. Find: The equivalent capacitance of the circuit ii. The total charge ii. The voltage drop across C3 iv. The charge on C1 C2 C3 2.00uF C1 6.00uF Vs 1µF 100v C4 4.00uF Figure 3Series-Parallel Circuit For the following circuit, determine: a) The total resistance RT b) The current IRI c) The current Ir6. d) The power consumed by R6.. . Ri 15 Ry 30s 15L 15 Rz 12v 30s2500mA 200mA Solve for the value of R3 as shown in the figure. 100mA 50mA "RI 250 13: R2 R3 R4 12
- SEARCH ASK CHAT MATH SOLVER Question A load is composed of a 4 ohm resistance connected in series with a 3 ohm inductive resistance. The load is connected across a 120 source. Compute: (a) current (b) voltage across the resistance (c) voltage across the inductor Recheck voltages using Vt=120 VWhat is the approximate value of the total resistance. R2 RS R11 4 kOhm 4 kOhm 5 kOhm R128 kOhm R310 kOhm R42 kOhm R62 kOhm R12712 kOhm5: For the coupled circuit shown in Figure 3, find the voltage across the capacitor of -j102 reactance with Vi-1040° V and V2-10290° V? j20 50 j50 50 -j100 Figure 3
- 8. Find the following: a. the voltage across R5 (Vo) b. the current through R5 11 1A ES 10k R1 27k R4 18k 10k Vo R5 27k R7 12k R6 6.8kFind the voltage across each inductor for the given circuit using the voltage divider rule. VL1 +m= L₁=10mH Vs=100 V, 60 Hz VL2 +mm- L₂=14mHQ3 Using superposition, determine the current through the inductance XL for each network in Figure below? R W H6 80 E₁ = 10 V 200 E₂ = 40 V / 60° 40 ell 360