Question

Transcribed Image Text:The three matrix operators for spin one satisfy sz Sy – Sy 8z = isz and
cyclic permutations. Show that
s = sz, (sz tisy )³ = 0.
For the sane in, m, can have the values im, m – 1, .., -m, while
A12 has eigenvalue m(m + 1). Thus
M? = m(m + 1)
±2
5 x 1 = 5 times
each once
6
15
4 x 8 = 32 times
+3/2
±1/2
3/2
each 8 times
4
±1
3 x 27 = 81 times
1
each 27 times
3
2 x 18 = 96 times
1/2
±1/2 each 48 times
1 × 12 = 42 times
0, each 42 times
Total 256 eigenvalues
A certain state | 4) is an eigenstate of L? and L,:
L'|v) = 1(l+ 1) h² |»),
mh|v) .
For this state calculate (La) and (L²).
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