The three lowest energy levels of a hydrogen atom are -13.6 eV, -3.4 eV, and -1.5 eV. Assume that there is only one way to occupy any one of these levels. Calculate the relative probability that a hydrogen atom in thermal equilibrium in a star, at temperature T = 9493 K, is in its first excited state (at -3.4 eV) relative to its ground state (at -13.6 eV). Write your answer in exponential form. Recall that Boltzmann's constant can be written as 8.617 x 10-5 eV K-1

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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The three lowest energy levels of a hydrogen atom are -13.6 eV, -3.4 eV, and -1.5 eV. Assume that there is only one way to occupy any one of these levels.
Calculate the relative probability that a hydrogen atom in thermal equilibrium in a star, at temperature T = 9493 K, is in its first excited state (at -3.4 eV) relative to its ground state (at -13.6 eV).
Write your answer in exponential form.
Recall that Boltzmann's constant can be written as 8.617 x 10-5 eV K-1
Transcribed Image Text:QUESTION 2 The three lowest energy levels of a hydrogen atom are -13.6 eV, -3.4 eV, and -1.5 eV. Assume that there is only one way to occupy any one of these levels. Calculate the relative probability that a hydrogen atom in thermal equilibrium in a star, at temperature T = 9493 K, is in its first excited state (at -3.4 eV) relative to its ground state (at -13.6 eV). Write your answer in exponential form. Recall that Boltzmann's constant can be written as 8.617 x 10-5 eV K-1
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