The test statistic of z=−2.85 is obtained when testing the claim that p=1/2. a. Using a significance level of α=0.05​, find the critical​ value(s). b. Should we reject H0 or should we fail to reject H0​?

The test statistic, t, is - 22.67. (Round to two decimal places as needed.) The P-value is 0.000. (Round to three decimal places as needed.) State the conclusion for the test. A. Reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda. B. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda. C. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda. D. Reject the null hypothesis. There is not sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda.

You are testing the null hypothesis that there is no linear relationship between two variables, X and Y. From your sample of n = 18, you determine that b, = 3.7 and S, = 1.3. a. What is the value of tsTAT? b. At the a = 0.05 level of significance, what are the critical values? c. Based on your answers to (a) and (b), what statistical decision should you make? d. Construct a 95% confidence interval estimate of the population slope, B1. a. What are the hypotheses to test? O A. Ho: B1 s0 H;: B, >0 O B. Ho: B1 +0 H;: B, = 0 С. Но В120 H;: B, <0 D. Ho: B1 =0 H;: B1 #0 tSTAT = (Round to two decimal places as needed.) b. The lower critical value is The upper critical value is (Round to four decimal places as needed.) c. What statistical decision should you make? A. Since tsTAT is greater than the upper critical value, do not reject the null hypothesis. B. Since tSTAT is between the two critical values, reject the null hypothesis. C. Since tsTAT is greater than the upper critical value, reject…

Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). With H1 :p>0.551, the test statistic is z=1.34.

Use the given information to find the ​p-value. ​Also, use a 0.05 significance level and state the conclusion about the null hypothesis​ (reject the null hypothesis or fail to reject the null​ hypothesis).   With  H 1​: p≠​0.377, the test statistic is z=3.06.

Q1: A researcher was interested in the effect of exercise on stress levels. For the general population, the distribution of the Stress Battery Scale scores is normal with the mean of µ = 25 and the standard deviation of σ = 5. A sample of n = 100 participants was asked to exercise for three weeks and then reported their stress levels. The sample mean was ?X = 23. Conduct a hypothesis test and determine the effect of exercise. Use the two-tailed test α = .01 1.Type the null and research hypotheses in complete sentences. 2.Cut off points 3.Standard error and z-score -show your computation process 4.Your conclusion thoroughly.

Which of the following is the best decision and conclusion based on the result below? H.: p = 0.10 Ha:p + 0.10 Critical Value: +1.645 Computed Test Statistics: z = 5.61 O a. Since the computed test statistics is less than the critical value, do not reject Ho. Therefore, we conclude that at 0.10 level of significance, there is enough evidence that the population proportion is different from 10%. O b. Since the computed test statistics is less than the critical value, do not reject Ho. Therefore, we conclude that at 0.10evel of significance, there is enough evidence that the population proportion is different from 10%. O c. Since the computed test statistics is greater than the critical value, reject Ho. Therefore, we conclude that at 0.10 level of significance, there is enough evidence that the population proportion is different from 10%. O d. Since the computed test statistics is less than the critical value, reject Ho. Therefore, we conclude that at 0.10 level of significance, there…

For the following claim, find the critical value. Assume that a simple random sample has been selected from a normally distributed population. Claim: The mean IQ score of statistics professors is greater than 130 Sample data: n= 28, x= 123, s=6. The significance level is a = 0.01.