The system (E – 3)uk + Vk = k, 3uk + (E – 5)vk = 4* %3D - (4.341) %3D can be solved for up: C(E² – 8E + 12)ux = 1 – 4* – 4*. (4.342) The general solution of this equation is Uk = c12* + c26k + 4*-1 – 4/sk – 19/25. (4.343) From the first of equations (4.341), we obtain -(E – 3)uk + k = c,2k – 3c26* – 4*-1 – 3/sk – 34/25. Vk = | (4.344) Therefore, the general solution of the system given by equations (4.331) is equations (4.343) and (4.344).

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