## Question 2The circuit diagram consists of a switch with two positions (1 and 2), a voltage source (\(V_s\)), a capacitor (\(C\)), and an inductor (\(L\)). - **Diagram Explanation:** - The voltage source (\(V_s\)) is 100V. - The capacitor value \(C\) is 10mF (millifarads). - The inductor value \(L\) is 20H (henrys). - The switch is initially in position 1 for a long time, allowing the capacitor to charge fully. - At \(t = 0\), the switch is moved to position 2, which starts the oscillation between the capacitor and inductor.### Tasks:1. **The period of oscillation (In Seconds):** - Calculate the period of oscillation for the LC circuit once the switch is moved to position 2.2. **Time after \(t = 0\) when Current is First Maximum (In Seconds):** - Determine the time it takes for the current to reach its first maximum value.3. **Energy stored in Inductor at Time of Max Current:** - Calculate the energy stored in the inductor at the moment when the current is at its maximum.4. **Energy stored in Capacitor at Time of Zero Current:** - Calculate the energy stored in the capacitor when the current in the circuit is zero.5. **Power of Inductor Maximum:** - Determine the maximum power reached in the inductor during the oscillation.This setup involves analyzing the LC oscillator and understanding energy transfer between the capacitor and inductor.

Two capacitors are in series Equivalent capacitance is Ceq=10×1010+10 =5 mF When switch is at position 1, capacitor is charged to voltage Vs at t=0, C=qVCeq=qVs when switch moved to position 2, circuit becomes an LC oscillator w=1LCeq =120×5×10-3=3.16 rad/secTIme period of oscillationT=2πw =2π3.16=1.988 sec period of oscillation The current is at its maximum when all the energy is stored in the inductor after t=0, current is maximum first time att=T4=1.9882=0.497 sec (negative maximum)t=3T4=3×1.9884=1.491 sec (Positive maximum) from law of energy consevation12Li2=12CeqVs2 =12×5×10-3×(100)2 =12Li2 =25 Joule ...Energy stored in inductor at max currentSame enegy will stored in capacitor at zero current12CeqVs2 = =25 Joule Energy stored in capacitor at zero currentNo resistance hence no power loss, maximum power of inductor =0