The switch in the circuit has been closed for a long time. It is opened at t = 0. At t = 0+, the current through the 1 µF capacitor is 5 V= 1Ω w oto t = 0 1 µF: 4Ω

A capacitor of 20.0 µF and a resistor of 100 2 are quickly connected in series to a battery of 6.00 V. What is the charge Q on the capacitor 0.00100 s after the connection is made? Q = C

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Find the value of the inductor  current when the switch is closed under DC condition

Assuming the capacitor is fully charged, what is the voltage across the capacitor 2 seconds after the switch is opened? E=33 V, R1=300 kſ, R2=300 k, C=10 uF R2 R1 ww + 55.2 V None of the above 31.5 V 47.3 V 23.6 V 39.4 V #6 C

The circuit below has fully adjusted to the closed switch. What is the currentthrough the inductor right before, and right after the switch is opened

The capacitance of a certain variable capacitor may be varied between limits of 1 × 10-20 F and 5×10-10 F by turning a knob attached to the movable plates. The capacitor is set to 5 × 10-10 F, and is charged by connecting it to a battery of EMF 200 V.  What is the charge on the plates? The battery is then disconnected and the capacitance changed to 1 × 10-10 F.  Assuming that no charge is lost from the plates, what is now the potential difference between them? How much mechanical work is done against electrical forces in changing the capacitance?

Determine the equivalent capacitance between AB in Figure 7 below; 5.0μF 24 μF 4.0 μ 12μF B 6.0 μ 8.0 μ