The structure is designed to support kN load. The structure consists of a boom and rod joined by pins (zero moment connections) at the junctions and supports. Perform a static analysis to determine the internal force in each structural member and the reaction forces at the supports. Use the last two digits of your ID for the Load P KN. 600 mm 50 mm d = 20 mm -800 mm B PKN

The structure is designed to support kN load. The structure consists of a boom and rod joined by pins (zero moment connections) at the junctions and supports. Perform a static analysis to determine the internal force in each structural member and the reaction forces at the supports. Use the last two digits of your ID for the Load P KN. 600 mm 50 mm d = 20 mm -800 mm B PKN

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

a=3 CVE 349 HOMEWORK 1 b=2.5 Q.1. d=3 P=12 27 9. a *Analyze the structure under given loading. *Design members 14,12,42,45,43,23,53 *Design joints 1,2,3,4 and 5. * Use parameters that are assigned to you. Those who use different parameters will be penalized and get 0. Units of a,b and c are meters and P is kN.
Dogs, like many animals, stand and walk on their toes. (Figure 1) shows the rear foot and leg of a 20kg dog along with the relevant distances and angles. The Achilles tendon pulls on the heel at an angle 15° from vertical. Part A What is the tension in the tendon if the dog is supporting one fourth of its weight on each foot? Express your answer with the appropriate units. F = N CalfmuscleAchillestendon15\deg 45\deg 9.0 cm 4.0 cm Calf muscle Achilles tendon -15° -45° 9.0 cm 4.0 cm
CHJ Equilbrium.pd - Adobe Acrobat Pro Eitended File Edt View Decument Comments Forms Tools Advanced Window Help H.W. Determine the horizontal and vertical components of force at pins A and D. D Ans: A = 24.0 kN A, = 12.0 kN D; = 18.0 kN D, = 24.0 kN %3D 2 m %3D 0.3 m %3D A -1.5 m B -1.5 m E ما من اتصال بالإنترنت
The column shown is fabricated from two C250 x 30 standard steel shapes (see Appendix B for its cross-sectional properties) that are oriented back-to-back with a gap of 33 mm between the two channels. The column is fixed at its base and free to translate in the y direction at its upper end. Translation in the z direction, however, is restrained at its upper end. A load P is applied at an offset distance of 430 mm from the channel flanges. Use the AISC equations given in Section 16.5, and assume that L = 4.1 m, s = 33 mm, E = 200 GPa, oy = 275 MPa, and (Gallow); = 145 MPa. Offset - distance e P Lateral bracing in z direction C250 x 30 L C250 x 30 Cross section.
PIOblem soMng Activity sheet (2).docx Microsoft Word (Product Activation Failed) References Mailings Review View 12 A A Aa =,=,|词|MT4| AaBbCcDc AaBbCcDc AaBbC AaBbCc ex, x' 1 Normal 1 No Spaci.. Heading 1 Heading 2 Font Paragraph Styles Chapter 1: Practice problems 1. An axial pull of 40000 N is acting on a bar consisting of three sections of length 30 cm,25 cm and 20 cm and of diameters 2 cm, 4 cm and 5 cm respectively as shown in figure 1. If the Young's modulus = 2 x 105 N/mm2, Calculate: (i) stress in each section and (ii) total extension of the bar. SECTION 3 SECTION 2 SECTION 1 2 cm Oia 4 cm Dia 5 cm Dla 40000 N 40000 N 30 cm 25 cm 20 cm figure 1. 2. A rod 200 cm long and off diameter 3.0 cm is subjected to an axial pull of 30 kN. If the Young's modulus of the material of the rod is 2 x 10° N/mm2, Calculate :(i) stress (ii) strain and (iii) the elongation of the rod. 3. Calculate the Young's modulus of a rod of diameter 30 mm and of length 300 mm which is subjected to a tensile…
Required information Stairs leading to a balcony are shown below. |400 lb dimensions in inches 40° 144 600 lb 32 22 16 38 30 30 For the 400 lb and 600 lb forces, and if F= 155 lb and P= 0, determine the reaction at point Dand the force supported by bar BE. The reaction at point Dand the force supported by bar BE are as follows: Dy= 410 Ib TBE = - 701.798 Ib
Solve the effective normal force on the rod CD Use units [N,mm] The mass of the load is: mk=59033kg
View Policies Current Attempt in Progress The automobile bumper jack is designed to support a 4610-N downward load. Begin with a free-body diagram of BCD and determine the force supported by roller C. Note that roller B does not contact the vertical column. 125 mm 125 mm 480 mm 4610 N 95 mm 220 mm 2310 mm Answer: C =
W LAB B LBC assume w = 4 kips/ft P= 5kips LAB=16 ft C LBC=8 ft What is the vertical reaction at A ? answer in kips
1. 1100 A. 30% B. 1.1 m 1.0 m A F= 255 N 0.5 m 1.5 m DGB WARNING! The figure is not drawn to scale. For the force in the chain CB, ca IMAGES NOTES DISCUSS UNITS STATS HELP PREFERENCES Part Description the magnitude of component parallel to the hinge axis of the door, (include units with answer) 0.5 m Answer 118.77 N Format Check the magnitude of the component parallel to the edge of the door that 218.17 N is perpendicular to the hinge axis, (include units with answer) Format Check Save 25 pts.7 75% 5% try penalty 31.67 pts.95% 5% try penalty Status Tr ● W #tries: ** Tr • W. #tries:
OMANTEL ooredoo Final Exam (page.. moodle1.du.edu.om Question 10 Not yet answered Marked out of 2.00 P Flag question Why do you need to determine the support reaction before going to calculate internal member forces of a truss? Select one: a. This reduces the calculation b. This results in reduction on the formulas used c. This procedure is not done at all d. This makes the isolated section more complicated Previous page Next page
The following illustration shows an idealized crane setup for lifting large machinery. The crane's rigid boom ABCD is supported at B by a cable, a rod pinned as D, and at C by a composite column. If the normal stress in the cable and rod should not exceed 70 MPa and the normal strain in the composite column should not exceed 0.1%, determine the maximum mass (in kg) of machinery that the crane can carry. Use r = 3 m. 2r B Aluminum cable: L = 2m E = 70 GPa D = 10 mm r Outer: Concrete L = 3m E = 150 GPa Douter= 60 mm Aluminum rod L = 4 m E = 70 GPa D = 25 mm 2r Inner core: Bronze L = 3m E = 100 GPa D = 30 mm D