College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- A force of 30 N stretches a spring 0.73 m from equilibrium. What is the value of the spring constant? Select one: a. 22 N/m b. 34 N/m C. 41 N/m O. d. 46 N/marrow_forwardThe spring return constant of a spring is 2000 N/m. How much will it crash in metres if a 100 kg person drops 30 cm high on the spring. take g=9.8 m/s2. Initially, the spring is neither stretched nor compressed. A. 0.193 m B. 0.542 m C. 0.784 m D. 0.948 m E. 1.22 marrow_forward3.A simple pendulum is suspended from the ceiling by means of a string of length 2.00 m. Now you start with the pendulum at 45.3 degrees with respect to the vertical, but rather than releasing it from rest, you give it a push downward. It swings to the other side and reaches a maximum angle of 56.6 degrees with respect to the vertical. What must have been the initial speed of the pendulum just after you pushed it? 2.45 m/s 4.20 m/s 3.41 m/s 6.30 m/sarrow_forward
- 3. Two masses of 1 kg and 0.5 kg are connected as in figure. The mass on the table is connected to a spring with spring constant k-80. The pulley is frictionless. The 0.5 kg mass is drop from rest at a height of 1 m from the floor. At this position the spring is in equilibrium A) Find the velocity as a function of height for the system. B) Find the acceleration.arrow_forward2. A 1.2 kg cart moving at 6.0 m/s [E] collides with a stationary 1.8 kg cart. The head-on collision is completely elastic and is cushioned by a spring. a. Find the velocity of each cart after the collision. b. The maximum compression of the spring during the collision is 2.0 cm. Find the spring constant.arrow_forwardPendulum: The _200 gʻ*bob" of a _1.2_m long pendulum is pulled back so that the string makes an angle of 15° from the vertical. A.) Determine the speed of the "bob" at the lowest point of the swing. B.) Determine the height at which the velocity of the “bob" will be 2 Vmax. 15°arrow_forward
- 16. One of the physical quantities shown below is a scalar that is always positive. Which one is it? Kinetic Energy Power Work Angular Momentum Translational Momentumarrow_forwardSuppose that during each step, the leg of the student, which is 0.90 meters long, swings through a total distance of 2.0 m. At the end of the swing, this foot rests on the ground for 0.2 s before the other leg begins its swing. a. At what speed does this student walk? (Think carefully about how far forward the student moves at each step.) b. The swinging leg reaches its maximum speed at the bottom of its arc. How many times faster is this maximum leg speed (measured with respect to the ground) than the average walking speed?arrow_forwardA mass m = 7.7 kg hangs on the end of a massless rope L = 1.86 m long. The pendulum is held horizontal and released from rest. 1) How fast is the mass moving at the bottom of its path? m/s Submit 2) What is the magnitude of the tension in the string at the bottom of the path? N Submit max 3) If the maximum tension the string can take without breaking is T N, what is the maximum mass that can be used? (Assuming that the mass is still released from the horizontal and swings down to its lowest point.) kg Submitarrow_forward
- A simple pendulum swings back and forth in a circular path. Including the effects of air resistance, determine which statement is true. There may be more than one correct answer. A. After the pendulum is released, it will never return to its original height. B. The total linear acceleration vector always points towards the center of the circular path as the pendulum swings back and forth. C. The work done by air resistance is always negative as the pendulum swings back and forth D. The work done by the tension force is always zero as the pendulum swings back and forth E. The gravitational force always produces a counterclockwise torque as the pendulum swings back and forth.arrow_forward2. A mass, M, is attached to a massless rod with length, L, to act as a pendulum. The mass is lifted through a 90° angle so that the rod is horizontal, then released. At the bottom of its swing the pendulum has velocity A. v = (gL)² B. v = gL C. v= V2gL D. v = MgL E. v = VM8Larrow_forward3. A bob on the end of a pendulum has a mass of 2.00kg. The rope of the pendulum Is 13.0 meters long. At the equilibrium point for the pendulum system, the bob is 10.0cm above the ground. The bob is pulled back to a height of 30.0cm above the ground. With the rope tight, the bob is release. a) Draw a diagram of this situation. Make note of the equilibrium point and the position from which the bob was released. b) Calculate the maximum speed of the bob. c) Calculate the speed of the bob when it is at a height of 17.0 cm above the ground. (arrow_forward
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