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The strength of a patient's reaction to a dose of x milligrams of a certain drug is R(x) = 8x√16 +0.5x for 0 ≤ x ≤ 140. The derivative R'(x) is called the sensitivity to the drug. Find R'(40), the sensitivity to a dose of 40 mg. R'(40) =

The strength of a patient's reaction to a dose of x milligrams of a certain drug is R(x) = 8x√16 +0.5x for 0 ≤ x ≤ 140. The derivative R'(x) is called the sensitivity to the drug. Find R'(40), the sensitivity to a dose of 40 mg. R'(40) =

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The strength of a patient's reaction to a dose of \( x \) milligrams of a certain drug is \( R(x) = 8\sqrt{16 + 0.5x} \) for \( 0 \leq x \leq 140 \). The derivative \( R'(x) \) is called the sensitivity to the drug. Find \( R'(40) \), the sensitivity to a dose of 40 mg. \[ R'(40) = \, \boxed{\phantom{R}} \]
Transcribed Image Text:The strength of a patient's reaction to a dose of \( x \) milligrams of a certain drug is \( R(x) = 8\sqrt{16 + 0.5x} \) for \( 0 \leq x \leq 140 \). The derivative \( R'(x) \) is called the sensitivity to the drug. Find \( R'(40) \), the sensitivity to a dose of 40 mg. \[ R'(40) = \, \boxed{\phantom{R}} \]
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